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Show that A(t)=300−250e^(0.2−0.02t) satisfies the differential equation ⅆAⅆt=6−0.02A with initial condition A(10)=50.

Show that A(t)=300−250e^(0.2−0.02t) satisfies the differential equation ⅆAⅆt=6−0.02A with initial condition A(10)=50.

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