In: Statistics and Probability
Listed below are the thorax lengths (in millimeters) of a sample of male fruit flies. Find the range and standard deviation for the given sample data.
0.84 0.83 0.66 0.87 0.88 0.91 0.65 0.71 0.71 0.87 0.660.84 0.83 0.66 0.87 0.88 0.91 0.65 0.71 0.71 0.87 0.66
Solution:
Given: Listed below are the thorax lengths (in millimeters) of a sample of male fruit flies.
0.84 0.83 0.66 0.87 0.88 0.91 0.65 0.71 0.71 0.87 0.66 0.84 0.83 0.66 0.87 0.88 0.91 0.65 0.71 0.71 0.87 0.66
We have to find: Range and standard deviation for the given sample data.
Range = L - S
where L = Largest observation = 0.91 and S = Smallest observation = 0.65
Thus
Range = L - S
Range = 0.91 - 0.65
Range =0.26
Standard Deviation:
Thus
x | x2 |
---|---|
0.84 | 0.7056 |
0.83 | 0.6889 |
0.66 | 0.4356 |
0.87 | 0.7569 |
0.88 | 0.7744 |
0.91 | 0.8281 |
0.65 | 0.4225 |
0.71 | 0.5041 |
0.71 | 0.5041 |
0.87 | 0.7569 |
0.66 | 0.4356 |
0.84 | 0.7056 |
0.83 | 0.6889 |
0.66 | 0.4356 |
0.87 | 0.7569 |
0.88 | 0.7744 |
0.91 | 0.8281 |
0.65 | 0.4225 |
0.71 | 0.5041 |
0.71 | 0.5041 |
0.87 | 0.7569 |
0.66 | 0.4356 |
Thus