Question

In: Statistics and Probability

Graded problem #2. The table below gives the cost per unit of a manufactured piece as...

Graded problem #2. The table below gives the cost per unit of a manufactured piece as a function of the number of units produced. Take the number of units produced as the explanatory variable, x, and the cost per unit as the response variable y.

Units 10 20 50 100 150 200

Cost 140 155 153 150 180 160

a. Predict the cost per unit when 80 units are produced

b. Find a 90% confidence interval for the slope b1

c. Find a 90% confidence interval for the predicted value you found in answer b.

Solutions

Expert Solution

X Y X * Y X2 Sxx =Σ (Xi - X̅ )2 Syy = Σ( Yi - Y̅ )2 Sxy = Σ (Xi - X̅ ) * (Yi - Y̅)
10 140 1400 100.0000 147.339 6136.106 266.777 1279.441
20 155 3100 400.0000 148.488 4669.440 1.778 91.109
50 153 7650 2500 151.932 1469.442 11.111 127.776
100 150 15000 10000 157.673 136.112 40.111 -73.889
150 180 27000 22500 163.414 3802.782 560.113 1459.447
200 160 32000 40000 169.155 12469.452 13.445 409.448
Total 530 938 86150 75500 672.000 28683.333 893.333 3293.333

X̅ = Σ (Xi / n ) = 530/6 = 88.3333
Y̅ = Σ (Yi / n ) = 938/6 = 156.3333

Equation of regression line is Ŷ = a + bX
b = ( n Σ(XY) - (ΣX* ΣY) ) / ( n Σ X2 - (ΣX)2 )
b = ( 6 * 86150 - 530 * 938 ) / ( 6 * 75500 - ( 530 )2)
b = 0.1148

a =( ΣY - ( b * ΣX ) ) / n
a =( 938 - ( 0.1148 * 530 ) ) / 6
a = 146.1912
Equation of regression line becomes Ŷ = 146.1912 + 0.1148 X

Part a)

= 146.1912 + 0.1148 X
= 155.3752

Estimated Error Variance (σ̂2) =
S2 = ( 893.3333 - 0.1148 * 3293.3333 ) / 6 - 2
S2 = 128.814659
S = 11.3497

Part b)

Confidence Interval

= 2.132 ( Critical value from t table )

90% confidence interval is -0.0281  < < 0.2577

Part c)

Confidence Interval of
= 146.1912 + 0.1148 X
= 155.3752

  = 2.132 ( From t table )
X̅ = (Xi / n ) = 530/6 = 88.3333
= 155.3752


90% confidence interval is ( 145.4252 < < 165.3252 )


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