Question

In: Mechanical Engineering

A system that operates in a reversible cycle receives energy by heat transfer from a 15.7oC...

A system that operates in a reversible cycle receives energy by heat transfer from a 15.7oC reservoir at a rate of 26.9 kW, and delivers energy by heat transfer to a 49.8oC reservoir. Determine the rate of heat transfer (kW) to the high temperature reservoir.

Solutions

Expert Solution

figure shows a reversible cycle system which receives energy from lower temperature reservoir and delivers to higher temperature reservoir hence it is either refrigerator or heat pump.

to calulate the rate of heat transfer Q1 (kW) to the high temperature reservoir. we have given values

Q2 = 26.9 kW

T1 =49.80 C = 49.8 +273 = 322.8 K

T2 =15.70 C = 15.7 +273 = 288.7 K

now for a reversible cycle,

we know that,

COP = T2 / (T1 - T2 ) = Q2 / (Q1 - Q2)

so, taking

T2 / (T1 - T2 ) = Q2 / (Q1 - Q2)

put all given values in above equation

288.7 / (322.8 - 288.7) = 26.9 / ( Q1 - 26.9)

by calculating this equation we have,

Q1 = 30.07 kW

samet mamat answered 2 years ago
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