In: Statistics and Probability
Suppose at random 32% of school children develop nausea and vomiting following holiday parties and that you conduct a study to examine this phenomenon, with a sample size of n=34. What is the probability that less than 21 children become sick?
This is a binomial distribution question with
n = 34
p = 0.32
q = 1 - p = 0.68
where
P(X < 21) = 1 (1.0) (0.0) + 34.0 (0.32) (0.0) + 561.0 (0.1024)
(0.0) + 5984.0 (0.0328) (0.0) + 46376.0 (0.0105) (0.0) + 278256.0
(0.0034) (0.0) + 1344904.0 (0.0011) (0.0) + 5379616.0 (0.0003)
(0.0) + 18156204.0 (0.0001) (0.0) + 52451256.0 (0.0) (0.0001) +
131128140.0 (0.0) (0.0001) + 286097760.0 (0.0) (0.0001) +
548354040.0 (0.0) (0.0002) + 927983760.0 (0.0) (0.0003) +
1391975640.0 (0.0) (0.0004) + 1855967520.0 (0.0) (0.0007) +
2203961430.0 (0.0) (0.001) + 2333606220.0 (0.0) (0.0014) +
2203961430.0 (0.0) (0.0021) + 1855967520.0 (0.0) (0.0031) +
1391975640.0 (0.0) (0.0045)
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