In: Chemistry
Given the following heats of reaction, use Hess’s law to calculate the heat of reaction (ΔHrxn) for the transformation below:
3 C(s) + 4 H2(g) à C3H8(g) ΔHrxn = ?
C3H8(g) + 5O2(g) à 3 CO2(g) + 4H2O(g) ΔH= - 2043 kJ/mol
C(s) + O2(g) à CO2(g) ΔH= - 393.5 kJ/mol
2H2(g) + O2(g) à 2 H2O(g) ΔH= - 483.6 kJ/mol
A. |
-1165.9 kJ/mol |
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B. |
- 104.7 kJ/mol |
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C. |
682.3 kJ/mol |
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D. |
-2920.1 kJ/mol |
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E. |
104.7 kJ/mol |
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F. |
1165.9 kJ/mol |
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G. |
2920.1 kJ/mol |
|
H. |
-4190.7 kJ/mol |
calculate the heat of reaction (ΔHrxn) for the transformation below:
Ca2+(aq) + 2 OH-(aq) + CO2(g) à CaCO3(s)+ H2O(l) ΔHrxn = ?
CaCO3(s) à CaO(s) + CO2(g) ΔH= - 178.1 kJ/mol
CaO(s) + H2O(l) à Ca(OH)2 (s) ΔH= - 65.3 kJ/mol
Ca(OH)2 (s) à Ca2+(aq) + 2 OH-(aq) ΔH= - 16.2 kJ/mol
A. |
-519.2 kJ/mol |
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B. |
-96.6 kJ/mol |
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C. |
31.3 kJ/mol |
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D. |
259.6 kJ/mol |
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E. |
519.2 kJ/mol |
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F. |
-31.3 kJ/mol |
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G. |
96.6 kJ/mol |
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H. |
-259.6 kJ/mol Calculate the value of work w for the internal energy change in the following reactions at 25.0°C. Which direction is the work being applied, by the system or on the system? 2 NH4NO3 (s) à 2 N2 (g) + 4 H2O (g) + O2 (g)
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3*( C(s) + O2(g) ----->
CO2(g)
ΔH = 3* -393.5 kJ )
2*( 2H2(g) + O2(g) ----> 2 H2O(g) ΔH = 2*-483.6 kJ )
3 CO2(g) + 4H2O(g) --> C3H8(g) +
5O2(g) ΔH = + 2043 kJ/mol
------------------------------------------------------------------
3 C(s) + 4 H2(g) ----->
C3H8(g)
ΔHrxn = ?
------------------------------------------------------------------
ΔHrxn = 3* -393.5 + 2*-483.6 + 2043
= -104.7 kj/mol
answer: B. -104.7 kj/mol
Ca2+(aq) + 2 OH-(aq) ----> Ca(OH)2
(s) ΔH = + 16.2
kJ/mol
Ca(OH)2 (s) ----> CaO(s) + H2O(l) ΔH = + 65.3 kJ/mol
CaO(s) + CO2(g) --->
CaCO3(s)
ΔH = + 178.1 kJ/mol
--------------------------------------------------------------------------
Ca2+(aq) + 2 OH-(aq) + CO2(g) ---> CaCO3(s)+ H2O(l)
ΔHrxn = ?
--------------------------------------------------------------------------
ΔHrxn = 16.2+ 65.3+178.1 = 259.6 kj/mol
answer: D
2 NH4NO3 (s) --> 2 N2 (g) + 4 H2O (g) + O2
(g)
as solid reactant converts into gaseous products , results
work is done by the system
w = -P*DV
= -DnRT
Dn = no of mole changed = 7
R = 8.314 j.k-1.mol-1
T = 25 c = 298 k
w = -7*8.314*298
= -17.34 kj/mol
answer: G. -17.34 kJ/mol; by system
2 SiO2 (g) + 3 C (s) ---> SiC (s) + 2 CO (g)
Dn = 2-2 = 0
w = 0 , work done = 0
answer: D. 0.000 J/mol; neither