1. Use Hess’s Law to determine the ΔH for the vaporization of methanol, CH3OH, given: 2...

1. Use Hess’s Law to determine the ΔH for the vaporization of methanol, CH3OH, given:

2 C (s) + 4 H2 (g) + O2 (g) → 2 CH3OH (g) −402.4 kJ/mol

2 C (s) + 4 H2 (g) + O2 (g) → 2 CH3OH (l) −477.2 kJ/mol

Expert Solution

2 C (s) + 4 H2 (g) + O2 (g) → 2 CH3OH (g) −402.4 kJ/mol......................Equation 1

2 C (s) + 4 H2 (g) + O2 (g) → 2 CH3OH (l) −477.2 kJ/mol..........................Equation 2

Let us take the reverse of equation 2:

2 CH3OH (l) → 2 C (s) + 4 H2 (g) + O2 (g) + 477.2 kJ/mol ...............................Equation 3

Adding equation 1 and equation 3 we get:

2 CH3OH (l) → 2 C (s) + 4 H2 (g) + O2 (g) + 477.2 kJ/mol

2 C (s) + 4 H2 (g) + O2 (g) → 2 CH3OH (g) −402.4 kJ/mol

Addition: 2 CH3OH (l) → 2 CH3OH (g) 74.8 kJ/ mole

DIviding both sides of the above equation by 2:

CH3OH (l) → CH3OH (g) 37.4 kJ/ mole

The delH of vapourisation of methanol is 37.4 kJ/ mole

queen_honey_blossom answered 1 year ago

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