In: Statistics and Probability
A government's department of transportation reported that in 2009, airline A led all domestic airlines in on-time arrivals for domestic flights, with a rate of 82.9%.
Complete parts a through e below.
a.What is the probability that in the next six flights, exactly four flights will be on time?
b. What is the probability that in the next six flights, two or fewer will be on time?
.c. What is the probability that in the next six flights, at least four flights will be on time?
d. d. What are the mean and standard deviation for this distribution?
A government's department of transportation reported that in 2009, airline A led all domestic airlines in on-time arrivals for domestic flights, with a rate of 82.9%.
Complete parts a through e below.
Binomial distribution used.
n=6, p=0.829
a.What is the probability that in the next six flights, exactly four flights will be on time?
P( x=4) =0.2072
Excel function used: =BINOM.DIST(4,6,0.829,FALSE)
b. What is the probability that in the next six flights, two or fewer will be on time?
P( x ≤2) =P( x=0)+P(x=1)+P( x=2)
=0.0000+0.0007+0.0088
=0.0095
.c. What is the probability that in the next six flights, at least four flights will be on time?
P( x≥4) =P( x=4)+P( x=5)+P(x=6)
=0.2072+0.4017+0.3246
=0.9335
d. d. What are the mean and standard deviation for this distribution?
Expectation = np = 4.974
Variance = np(1 - p) = 0.850554
Mean = 4.974, sd=0.9223
Binomial Probabilities |
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Data |
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Sample size |
6 |
|
Probability of an event of interest |
0.829 |
|
Statistics |
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Mean |
4.974 |
|
Variance |
0.8506 |
|
Standard deviation |
0.9223 |
|
Binomial Probabilities Table |
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X |
P(X) |
|
0 |
0.0000 |
|
1 |
0.0007 |
|
2 |
0.0088 |
|
3 |
0.0570 |
|
4 |
0.2072 |
|
5 |
0.4017 |
|
6 |
0.3246 |