Solution :
Given that,
Point estimate = sample mean =
= 6.8
Population standard deviation =
= 0.2
Sample size = n = 59
At 90% confidence level the z is ,
= 1 - 90% = 1 - 0.90 = 0.10
/ 2 = 0.10 / 2 = 0.05
Z
/2
= Z0.05 = 1.645
Margin of error = E = Z
/2*
(
/
n)
= 1.645 * (0.2 /
59 )
= 0.043
At 90% confidence interval estimate of the population mean
is,
- E <
<
+ E
6.8 - 0.043 <
< 6.8 + 0.043
6. 76 <
< 6.84
(6.76 , 6.84)