* Calculus****** * * + = ~.~ Let P1 be the plane defined by the equation...

******* Calculus************

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Let P1 be the plane defined by the equation 2x−8y+5z = 2 and let P2 be the plane defined by the equation 3x + 2y − z = 7. Find the equation for a new plane, P3, which is perpendicular to both P1 and P2, and also which passes through the point (-3,1,2). HINT: If P3 is perpendicular to P1 and P2, then the normal vector for P3 should be perpendicular to the normal vectors of P1 and P2.

PLEASE GRAPH P1, P2, and P3 on the same set of axes.

please explain as much as you can thank you :)))

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Expert Solution

However, To graph 3D planes P1, P2, P3 it will be best to use some 3D graphing calculator or software. Graph will look like this :

I hope it helps. Please feel free to revert back with further queries (if any) in comments. Thanks!

Colby Messinger answered 1 year ago

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******* Calculus************ * * + = ~.~ Let P1 be the plane defined by the equation...

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* Calculus****** * * + = ~.~ Let P1 be the plane defined by the equation...