In: Chemistry
One of the emission lines of the hydrogen atom has a wavelength of 93.07 nm. In what region of the electromagnetic spectrum is this emission found? Determine the initial value of n associated with this emission.
One of the emission lines of the hydrogen atom has a wavelength of 93.07 nm
wavelength between 90 - 400nm . It is UV region
The region of the electromagnetic spectrum is this emission found ultraviolent region
nf = 1
= 93.07nm = 93.07*10^-7 cm
RH = 109737cm^-1
1/ = RH( 1/nf^2 - 1/ni^2)
1/93.07*10^-7 = 109737(1/(1)^2 - 1/(ni)^2 )
107446 = 109737(1- 1/ni^2)
107446/109737 = (1-1/ni^2 )
0.979 = 1-1/ni^2
0.979-1 = -1/ni^2
-0.021 = -1/ni^2
ni^2 = 1/0.021
ni^2 = 49
ni = 7
The initial value of n associated with this emission ni = 7