In: Statistics and Probability
Two plots at Rothamsted Experimental Station were studied for production of wheat straw. For a random sample of years, the annual wheat straw production (in pounds) from one plot was as follows.
6.19 | 6.40 | 6.82 | 6.75 | 7.31 | 7.18 |
7.06 | 5.79 | 6.24 | 5.91 | 6.14 |
Use a calculator to verify that, for this plot, the sample
variance is s2 ≈ 0.274.
Another random sample of years for a second plot gave the following
annual wheat production (in pounds).
6.96 | 7.73 | 7.03 | 7.31 | 7.22 | 5.58 | 5.47 | 5.86 |
Use a calculator to verify that the sample variance for this
plot is s2 ≈ 0.761.
Test the claim that there is a difference (either way) in the
population variance of wheat straw production for these two plots.
Use a 5% level of signifcance.
(a) What is the level of significance?
State the null and alternate hypotheses.
Ho: σ12 = σ22; H1: σ12 > σ22Ho: σ12 > σ22; H1: σ12 = σ22 Ho: σ22 = σ12; H1: σ22 > σ12Ho: σ12 = σ22; H1: σ12 ≠ σ22
(b) Find the value of the sample F statistic. (Use 2
decimal places.)
What are the degrees of freedom?
dfN | |
dfD |
What assumptions are you making about the original distribution?
The populations follow independent normal distributions.The populations follow independent chi-square distributions. We have random samples from each population. The populations follow independent normal distributions. We have random samples from each population.The populations follow dependent normal distributions. We have random samples from each population.
(c) Find or estimate the P-value of the sample test
statistic. (Use 4 decimal places.)
p-value > 0.2000.100 < p-value < 0.200 0.050 < p-value < 0.1000.020 < p-value < 0.0500.002 < p-value < 0.020p-value < 0.002
(d) Based on your answers in parts (a) to (c), will you reject or
fail to reject the null hypothesis?
At the α = 0.05 level, we reject the null hypothesis and conclude the data are not statistically significant.At the α = 0.05 level, we reject the null hypothesis and conclude the data are statistically significant. At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are statistically significant.
(e) Interpret your conclusion in the context of the
application.
Fail to reject the null hypothesis, there is sufficient evidence that the variance in annual wheat production differs between the two plots.Reject the null hypothesis, there is insufficient evidence that the variance in annual wheat production differs between the two plots. Reject the null hypothesis, there is sufficient evidence that the variance in annual wheat production differs between the two plots.Fail to reject the null hypothesis, there is insufficient evidence that the variance in annual wheat production differs between the two plots.
First Plot ( X ) | Σ ( Xi- X̅ )2 | Second Plot ( Y ) | Σ ( Yi- Y̅ )2 | |
6.19 | 0.1129 | 6.96 | 0.0992 | |
6.4 | 0.0159 | 7.73 | 1.1772 | |
6.82 | 0.0864 | 7.03 | 0.1482 | |
6.75 | 0.0502 | 7.31 | 0.4422 | |
7.31 | 0.6147 | 7.22 | 0.3306 | |
7.18 | 0.4277 | 5.58 | 1.1342 | |
7.06 | 0.2852 | 5.47 | 1.3806 | |
5.79 | 0.5417 | 5.86 | 0.6162 | |
6.24 | 0.0818 | |||
5.91 | 0.3795 | |||
6.14 | 0.149 | |||
Total | 71.79 | 2.745 | 53.16 | 5.3284 |
Mean X̅ = Σ Xi / n
X̅ = 71.79 / 11 = 6.526
Sample Standard deviation SX = √ ( (Xi - X̅
)2 / n - 1 )
SX = √ ( 2.745 / 11 -1 ) = 0.524
S2X = ( 2.745 / 11 -1 ) = 0.274
Mean Y̅ = ΣYi / n
Y̅ = 53.16 / 8 = 6.645
Sample Standard deviation SY = √ ( (Yi - Y̅
)2 / n - 1 )
SY = √ ( 5.3284 / 8 -1) = 0.872
S2Y = ( 5.3284 / 8 -1) = 0.760
Part a)
α = 0.05
Ho: σ12 = σ22; H1: σ12 ≠ σ22
Part b)
Test Statistic :-
f = 0.2746 / 0.7604
f = 0.36
Degree of freedom
Numerator = 10
Denominator = 7
The populations follow independent normal distributions
Part c)
P value = 2 * P ( f > 0.3611 ) = 0.1408
0.100 < p-value < 0.200
Part d)
Reject null hypothesis if P value < α = 0.05
Since P value = 0.1408 > 0.05, hence we fail to reject the null
hypothesis
Conclusion :- We Fail to Reject H0
Part e)
At the α = 0.05 level, we fail to reject the null hypothesis and conclude the data are not statistically significant.
Part f)
Fail to reject the null hypothesis, there is insufficient evidence that the variance in annual wheat production differs between the two plots.