Question

Scenario

Certified Behavior Analysts claim that their procedures are more effective than any other.  Their procedures are clear-cut analytics that anyone can learn and apply. It’s not an art they proclaim, but a science.  You decide to put it to test.  You interview and survey the parents of autistic kids, loved ones of the depressed, and former sufferers of phobias, who had been treated with Behavior Therapy, Drug Therapy, and Play Therapy.  Your survey generates a score from 1-100 with higher values indicating greater effectiveness of the therapy and 85 and above indicates complete resolution of the problem.  

            Behavior Therapy                   Drug Therapy              Play Therapy

            58, 65, 71, 59,                         59, 68, 32, 44              58, 61, 50, 60

            81, 74, 83, 63                          38, 41, 30, 51              64, 62, 85, 57

Instructions:

1. Using the above data calculate the one-way analysis of variance in JASP. Report the F-ratio in APA style, including the p-value and eta-squared (treatment magnitude).

2. If the one-way ANOVA shows a significant difference among the groups, then calculate post hoc test to determine which groups are different – be sure you compare each group to each other group. Report the significant differences among the groups. If the one-way ANOVA does not show a significant difference, then state no difference.  

3. Calculate the mean and standard deviations for all three groups and report in an APA table. You may use the one generated by JASP.

4. Write a short APA summary of your conclusions. Make sure to use the data to support conclusions.

Answer 1

anova table
	SS	df	MS	F	p-value	F-critical
Between:	2403.58	2	1201.79	9.77	0.0010	3.47
Within:	2584.25	21	123.06
Total:	4987.83	23
					α =	0.05
			conclusion :	p-value<α , reject null hypothesis

b)

Level of significance	0.05
no. of treatments,k	3
DF error =N-k=	21
MSE	123.060
q-statistic value(α,k,N-k)	3.5800
critical value = q*√(MSE/n)

			confidence interval
population mean difference	critical value	lower limit	upper limit	result
µ1-µ2	23.88	14.04	9.83	37.92	means are different
µ1-µ3	7.13	14.04	-6.92	21.17	means are not different
µ2-µ3	-16.75	14.04	-30.79	-2.71	means are different

................

	A	B	C
count, ni =	8	8	8
mean , x̅ i =	69.250	45.38	62.13
std. dev., si =	9.573	13.201	10.162

...................

Please revert back in case of any doubt.

Please upvote. Thanks in advance.