Calculate the change in Entropy

A 288 kg block of ice at 0∘C is placed in a large lake the temperature of the lake is just slightly higher than 0∘C and the ice melts very slowly.

i) what is the entropy change of ice

Expert Solution

The change in entropy is defined as the change in energy of a system going through a thermodynamic process divided by the temperature of the system. In this problem, the ice experiences the melting process, so the heat required for it is its mass multiplied by the latent heat of fusion.

The change in entropy of the ice :-

Given = mass of ice = 288 kg

Latent heat of fusion constt .Lf=3.34×10^5

T- Temperature

Entropy =mass× latent heat/T

ΔS=ΔQ/T

S-Entropy

T- Temperature

Q- heat

Q=mass*latent heat of fusion

=M×Lf

ΔSi=ΔQi/Ti,=mLf/T =288×34×10^5/273,=961.92×10^5/273,=3.52×105J/k

Naveen yadav answered 3 years ago

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