Question

25% of patients who had been hospitalized for an acute myocardial infarction did not fill their cardiac medication by the seventh day of being discharged. Suppose there are 14 people who have been hospitalized for an acute myocardial infarction

. a) State the random variable.

b) List the given numeric values with the correct symbols. ? = 14 ? = 0.25

c) Compute the mean. Round final answer to 2 decimal places. Which of the following is the correct interpretation of the mean?

d) Compute the standard deviation. Round final answer to 2 decimal places.

Answer 1

Solution:-

We have

There are 25% of patient who had been hospitalized for an actual myocardial infarction did fill their cardiac medication

That is,

p=25% =0.25

Suppose there are 14 people who have been hospitalized for an acute myocardial infarction

That is,

n=14

A) State random variable

-----> Let X: The number of patients who had been hospitalized for an acute myocardial infarction did not fill their cardiac medication by the seventh day of being discharged.

X~ Binomial (n,p) distribution

B)List the given numeric values with the correct symbols. ? = 14 ? = 0.25

-----> n= 14 and p=0.25

Therefore,

X~ Binomial (n=14, p=0.25) distribution

pmf of X is given by

Mean and Standard deviation of X is

C)Compute the mean?

-----> Mean = n*p =14 * 0.25 = 3.50

Interpretation:-

On an average, 3.50 patients who had been hospitalized for an acute myocardial infarction did not fill their cardiac medication by the seventh day of being discharged.

D)Compute standard deviation?

---->

The standard deviation formula (for binomial distribution) is