In: Chemistry
You have a 593.3 mL sample of 2.511 M HA (Ka = 8.56 ⋅ 10 − 2 ). Calculate the pH of the best buffer.
HA ------------------------> H+ + A-
2.511 0 0
-x +x +x
2.511-x x x
Ka = x^2 / 2.511-x = 8.56 x 10^-2
x^2 + 8.56 x 10^-2 x - 0.2149 = 0
x = 0.4227
[H+] = 0.4227 M
pH = -log [H+]
pH = -log (0.4227)
pH = 0.374