In: Statistics and Probability
Hello! I have a question about the following problem, not sure how to approach it...
This is from Mathematical Statistics and Data Analysis, Chapter 11, Problem 11.41
The Hodges-Lehmann shift estimate is defined to be d =median(Xi −Yj), where X1 , X2 , . . . , Xn are independent observations from a distribution F and Y1,Y2,...,Ym are independent observations from a distribution G and are independent of the Xi.
Show that if F and G are normal distributions, then E(d) = μx − μy.
Why is d robust to outliers?
Use the bootstrap to approximate the sampling distribution and the standard error of d.
From the bootstrap approximation to the sampling distribution, form an approximate 90% confidence interval for d
Thank you