In: Chemistry
Why iron(III) solutions are more soluble in acidic solutions using Le Chatalier's principle?
First, denote the equations:
Fe3+(aq) + H2O(l)
there might be equilbirium:
Fe3+(aq) + 3H2O(l) <--> Fe(OH)3(s) + 3H+(aq)
therefore
let FeX3 be a generic salt which is not that soluble
FeX3(s) = Fe+3 + 3X-
in solution
Note that Fe3+ forms equilbirium with water, so Fe(OH)3 precipitates.... therefore, Fe+3 decreases in solution
according to Le Chatalier's principle
The statement is as follows:
If any equilibrium is disturbed, that is, change in conditions such as P,T, concentration, partial pressure, etc.., the system will counterbalance such change in order to favour the system's equilbirium.
We are decreasing Fe+3
so
the shift in:
FeX3(s) = Fe+3 + 3X-
favours more FeX3(s) going into solution as Fe+3 and 3X- in order to counterbalance the loss of Fe+3 ions in Fe(OH)3(S)