In: Statistics and Probability
Performance Data | ||
Group | Test 1 | Test 2 |
1 | 96 | 85 |
1 | 96 | 88 |
1 | 91 | 81 |
1 | 95 | 78 |
1 | 92 | 85 |
1 | 93 | 87 |
1 | 98 | 84 |
1 | 92 | 82 |
1 | 97 | 89 |
1 | 95 | 96 |
1 | 99 | 93 |
1 | 89 | 90 |
1 | 94 | 90 |
1 | 92 | 94 |
1 | 94 | 84 |
1 | 90 | 92 |
1 | 91 | 70 |
1 | 90 | 81 |
1 | 86 | 81 |
1 | 90 | 76 |
1 | 91 | 79 |
1 | 88 | 83 |
1 | 87 | 82 |
0 | 93 | 74 |
0 | 90 | 84 |
0 | 91 | 81 |
0 | 91 | 78 |
0 | 88 | 78 |
0 | 86 | 86 |
0 | 79 | 81 |
0 | 83 | 84 |
0 | 79 | 77 |
0 | 88 | 75 |
0 | 81 | 85 |
0 | 85 | 83 |
0 | 82 | 72 |
0 | 82 | 81 |
0 | 81 | 77 |
0 | 86 | 76 |
0 | 81 | 84 |
0 | 85 | 78 |
0 | 83 | 77 |
0 | 81 | 71 |
A different teacher wants to see if Test 1 was predictive of Test 2. Please answer the following questions based on the data set.
A) What is the y intercept?
B) What is the slope?
C) What is the amount of variance explained in Test 2 by Test 1?
D) Assuming a student got an 84 on Test 1, what is the predicted score for Test 2? Please round to the nearest whole number.
E). For the Excel Data Set please find and report for Test 1 and Test 2 the Mean, SD, and the tolerance levels for both for which there would be any outliers (i.e., the value for which a score must be less than to be consider an outlier and the value for which a number must greater than to be considered an outlier.
Sol:
Peform regression in excel
Data >Data analysis >Regression
Test1 as X
Test 2 as Y
click ok
Output
SUMMARY OUTPUT | ||||||
Regression Statistics | ||||||
Multiple R | 0.450532 | |||||
R Square | 0.202979 | |||||
Adjusted R Square | 0.18354 | |||||
Standard Error | 5.519503 | |||||
Observations | 43 | |||||
ANOVA | ||||||
df | SS | MS | F | Significance F | ||
Regression | 1 | 318.1015 | 318.1015 | 10.44157 | 0.002432 | |
Residual | 41 | 1249.061 | 30.46491 | |||
Total | 42 | 1567.163 | ||||
Coefficients | Standard Error | t Stat | P-value | Lower 95% | Upper 95% | |
Intercept | 37.11728 | 13.95839 | 2.659137 | 0.011124 | 8.927732 | 65.30682 |
Test1 | 0.506662 | 0.156796 | 3.231342 | 0.002432 | 0.190006 | 0.823319 |
A) What is the y intercept?
y intercept=37.11728
B) What is the slope?
slope=0.506662
C) What is the amount of variance explained in Test 2 by Test 1?
R sq=0.202979
=20.3%
20.3% varaince in Test 2 is explained by Test1
D) Assuming a student got an 84 on Test 1, what is the predicted score for Test 2? Please round to the nearest whole number.
we have
Test2=37.11728+ 0.506662*test1
for test 1=84,predicted test 2
Test2=37.11728+ 0.506662*84
Test2= 79.67689
Test 2=80
predicted score for Test 2=80
Solution-E
fivenumber sumamry for test 1
Fivenum syummary is MIN,Q1,Q2,Q3,MAX
79.0 85.0 90.0 92.5 99.0
IQR=Q3-Q1=92.5-85.0=7.5
lower fence
Q-1.5IQR
85.0-1.5*7.5
=73.75
values below 73.75 are outliers
upper fence
Q3+1.5IQR
fivenumber sumamry for test 2
70 78 82 85 96
IQR=Q3-Q1=85-78=7
lower fence
Q-1.5IQR
78-1.5*7
= 67.5
upper fence
=Q3+1.5IQR
85+1.5*7
= 95.5
Test1 | Test2 | ||
Mean | 88.86046512 | Mean | 82.13953 |
Standard Error | 0.828333659 | Standard Error | 0.931533 |
Lower fence | 73.75 | Lower fence | 67.5 |
Upper fence | 103.75 | Upper fence | 95.5 |