In: Statistics and Probability
61 |
80 |
68 |
83 |
78 |
66 |
62 |
56 |
Solution:- Given that 61,80,68,83,78,66,62,56
a. The mean = sum of terms/number of terms
= 558/8
= 69.25
Median = 67
The median is the middle number in a sorted list of numbers. So, to
find the median, we need to place the numbers in value order and
find the middle number.
Ordering the data from least to greatest, we get:
56 61 62 66 68 78 80 83
As you can see, we do not have just one middle number but we have a pair of middle numbers, so the median is the average of these two numbers:
Median = (66+68)/2 = 67
mode : no
mode
Explanation:-
The mode of a set of data is the value in the set that occurs most
often.
Ordering the data from least to greatest, we get:
56 61 62 66 68 78 80 83
Since each value occurs only once, there is no mode for this data set.
b.
The range = 27
The range is the difference between the highest and lowest values in the data set.
Ordering the data from least to greatest, we get:
56 61 62 66 68 78 80 83
The lowest value is 56.
The highest value is 83.
The range = 83 - 56 = 27.
Variance = 98.5
Standard deviation = 9.9247
c. Q1 = 61.5
Explanation
The first quartile (or lower quartile or 25th percentile) is the median of the bottom half of the numbers. So, to find the first quartile, we need to place the numbers in value order and find the bottom half.
56 61 62 66 68 78 80 83
So, the bottom half is
56 61 62 66
The median of these numbers is 61.5.
Q2 = 67
Q3 = 79
Explanation
The third quartile (or upper quartile or 75th percentile) is the median of the upper half of the numbers. So, to find the third quartile, we need to place the numbers in value order and find the upper half.
56 61 62 66 68 78 80 83
So, the upper half is
68 78 80 83
The median of these numbers is 79.
d. The interquartile range of the data set is 17.5.
Explanation
The interquartile range is the difference between the third and first quartiles.
The third quartile is 79.
The first quartile is 61.5.
The interquartile range = 79 - 61.5 = 17.5.
e. No outliers.
f. stem and leaf plot :
stem | leaf |
5 | 6 |
6 | 1 2 6 8 |
7 | 8 |
8 | 0 3 |
g. box plot :
h. P(X < 79) = P(X-mean)/sd) < (79-69.25)/9.9247)
= P(Z < 0.9824)
= 0.8365