In: Statistics and Probability
Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.
| 7.4 | 6.3 | 10.7 | 7.0 | 7.5 | 9.7 | 7.2 |
| 9.0 | 7.3 | 11.3 | 6.8 | 7.9 | 5.5 | 7.7 |
| 8.6 | 8.1 | 6.5 | 11.6 | 7.8 | 9.7 | 11.8 |
| 6.3 | 6.8 | 8.7 | 7.7 | 7.0 | 7.9 |
(a) Calculate a point estimate of the mean value of strength for
the conceptual population of all beams manufactured in this
fashion. [Hint: Σxi = 219.8.] (Round
your answer to three decimal places.)
MPa
(b) Calculate a point estimate of the strength value that separates
the weakest 50% of all such beams from the strongest 50%.
MPa
(c) Calculate a point estimate of the population standard deviation
σ. [Hint: Σxi2 =
1863.16.] (Round your answer to three decimal places.)
MPa
(d) Calculate a point estimate of the proportion of all such beams
whose flexural strength exceeds 10 MPa. [Hint: Think of an
observation as a "success" if it exceeds 10.] (Round your answer to
three decimal places.)
(e) Calculate a point estimate of the population coefficient of
variation σ/μ. (Round your answer to four decimal
places.)
Solution:
We are given data on flexural strength (MPa) for concrete beams of a certain type.
| 7.4 | 6.3 | 10.7 | 7.0 | 7.5 | 9.7 | 7.2 |
| 9.0 | 7.3 | 11.3 | 6.8 | 7.9 | 5.5 | 7.7 |
| 8.6 | 8.1 | 6.5 | 11.6 | 7.8 | 9.7 | 11.8 |
| 6.3 | 6.8 | 8.7 | 7.7 | 7.0 | 7.9 |
Part a) Calculate a point estimate of the mean value of strength for the conceptual population of all beams manufactured in this fashion.
Given: 
and n = Number of observations = 27
Since sample mean is an unbiased estimator of population mean.
Thus a point estimate of the mean value of strength in of all beams manufactured in this fashion is given by:


MPa
Part b) Calculate a point estimate of the strength value that separates the weakest 50% of all such beams from the strongest 50%.
That is we have to find median.
Thus we need to arrange data in ascending order.
| Sr No | |
| 1 | 5.5 |
| 2 | 6.3 |
| 3 | 6.3 |
| 4 | 6.5 |
| 5 | 6.8 |
| 6 | 6.8 |
| 7 | 7 |
| 8 | 7 |
| 9 | 7.2 |
| 10 | 7.3 |
| 11 | 7.4 |
| 12 | 7.5 |
| 13 | 7.7 |
| 14 | 7.7 |
| 15 | 7.8 |
| 16 | 7.9 |
| 17 | 7.9 |
| 18 | 8.1 |
| 19 | 8.6 |
| 20 | 8.7 |
| 21 | 9 |
| 22 | 9.7 |
| 23 | 9.7 |
| 24 | 10.7 |
| 25 | 11.3 |
| 26 | 11.6 |
| 27 | 11.8 |
when n is odd





Thus a point estimate of the strength value that separates the weakest 50% of all such beams from the strongest 50% is 7.7 MPa.
Part c) Calculate a point estimate of the population standard deviation σ.

Sample standard deviation is an unbiased estimator of population standard deviation and it is given by:







That is:
Part d) Calculate a point estimate of the proportion of all such beams whose flexural strength exceeds 10 MPa.
Success = beams whose flexural strength exceeds 10 MPa.
From given data we have number of observations > 10 MPa = 4
Thus



Part e) Calculate a point estimate of the population coefficient of variation σ/μ.
Coefficient of Variation ( CV ) is given by:



