In: Statistics and Probability
Consider the accompanying data on flexural strength (MPa) for concrete beams of a certain type.
7.4 | 6.3 | 10.7 | 7.0 | 7.5 | 9.7 | 7.2 |
9.0 | 7.3 | 11.3 | 6.8 | 7.9 | 5.5 | 7.7 |
8.6 | 8.1 | 6.5 | 11.6 | 7.8 | 9.7 | 11.8 |
6.3 | 6.8 | 8.7 | 7.7 | 7.0 | 7.9 |
(a) Calculate a point estimate of the mean value of strength for
the conceptual population of all beams manufactured in this
fashion. [Hint: Σxi = 219.8.] (Round
your answer to three decimal places.)
MPa
(b) Calculate a point estimate of the strength value that separates
the weakest 50% of all such beams from the strongest 50%.
MPa
(c) Calculate a point estimate of the population standard deviation
σ. [Hint: Σxi2 =
1863.16.] (Round your answer to three decimal places.)
MPa
(d) Calculate a point estimate of the proportion of all such beams
whose flexural strength exceeds 10 MPa. [Hint: Think of an
observation as a "success" if it exceeds 10.] (Round your answer to
three decimal places.)
(e) Calculate a point estimate of the population coefficient of
variation σ/μ. (Round your answer to four decimal
places.)
Solution:
We are given data on flexural strength (MPa) for concrete beams of a certain type.
7.4 | 6.3 | 10.7 | 7.0 | 7.5 | 9.7 | 7.2 |
9.0 | 7.3 | 11.3 | 6.8 | 7.9 | 5.5 | 7.7 |
8.6 | 8.1 | 6.5 | 11.6 | 7.8 | 9.7 | 11.8 |
6.3 | 6.8 | 8.7 | 7.7 | 7.0 | 7.9 |
Part a) Calculate a point estimate of the mean value of strength for the conceptual population of all beams manufactured in this fashion.
Given:
and n = Number of observations = 27
Since sample mean is an unbiased estimator of population mean.
Thus a point estimate of the mean value of strength in of all beams manufactured in this fashion is given by:
MPa
Part b) Calculate a point estimate of the strength value that separates the weakest 50% of all such beams from the strongest 50%.
That is we have to find median.
Thus we need to arrange data in ascending order.
Sr No | |
1 | 5.5 |
2 | 6.3 |
3 | 6.3 |
4 | 6.5 |
5 | 6.8 |
6 | 6.8 |
7 | 7 |
8 | 7 |
9 | 7.2 |
10 | 7.3 |
11 | 7.4 |
12 | 7.5 |
13 | 7.7 |
14 | 7.7 |
15 | 7.8 |
16 | 7.9 |
17 | 7.9 |
18 | 8.1 |
19 | 8.6 |
20 | 8.7 |
21 | 9 |
22 | 9.7 |
23 | 9.7 |
24 | 10.7 |
25 | 11.3 |
26 | 11.6 |
27 | 11.8 |
when n is odd
Thus a point estimate of the strength value that separates the weakest 50% of all such beams from the strongest 50% is 7.7 MPa.
Part c) Calculate a point estimate of the population standard deviation σ.
Sample standard deviation is an unbiased estimator of population standard deviation and it is given by:
That is:
Part d) Calculate a point estimate of the proportion of all such beams whose flexural strength exceeds 10 MPa.
Success = beams whose flexural strength exceeds 10 MPa.
From given data we have number of observations > 10 MPa = 4
Thus
Part e) Calculate a point estimate of the population coefficient of variation σ/μ.
Coefficient of Variation ( CV ) is given by: