Question

Write a program which asks the user for grade, in integer form, from 0 to 100.

If the user's response is negative or greater than 100, insult them.

Otherwise, use if / else statements to print out the letter grade corresponding to the user's input.

• 90 - 100 : A
• 80 - 89 : B
• 70 - 79 : C
• 60 - 69 : D
• 0 - 59 : F

Then, write a second version of the program which uses a switch instead of if else. (HINT: divide the user's response by 10)

Answer 1

C++ CODE::

#include <iostream>
using namespace std;
int main() {
  
    int grade;

    while(1)
    {
        cout<<"Enter grade: ";
        cin>> grade;
        if(grade >= 0 && grade <= 100)
        {
            break;
        }
        cout<<"\nError: Grade is not in required range.Please Enter again.."<<endl;
    }
    cout<<"Using If- else: "<<endl;
        if(grade >= 90 && grade <= 100)
        {
           cout<<"Your grade is A"<<endl;
        }
        else if(grade >= 80 && grade<= 89)
        {
            cout<<"Your grade is B"<<endl;
        }
        else if(grade >= 70 && grade <= 79)
        {
            cout<<"Your grade is C"<<endl;
        }
        else if(grade>= 60 && grade<= 69)
        {
            cout<<"Your grade is D"<<endl;
        }
        else
        {
            cout<<"Your grade is F"<<endl;
        }
    cout<<"Using switch - case: "<<endl;

    int choice = grade/10;

    switch(choice)
    {
        case 9: cout<<"Your grade is A"<<endl;
        break;
         case 8: cout<<"Your grade is B"<<endl;
        break;
         case 7: cout<<"Your grade is C"<<endl;
        break;
         case 6: cout<<"Your grade is D"<<endl;
        break;
        default :  cout<<"Your grade is F"<<endl;

    }


}

SCREENSHOT::