Question

Write a program in Cthat asks for an integer y ≥ 0, which represents a year. The program should output “YES” if the y is leap (and “NO” if it is not). A leap year is a year that has 366 days (or February 29), that is a year which is divisible by 4 but, not by 100; in exception if it is divisible by 400.

Answer 1

Program:

#include<stdio.h>

void main()
{
   int y;
   int leap = 0;
  
   printf("\nEnter the year: ");
   scanf("%d",&y);
  
   if(y%4 == 0 && y%100 != 0)
   {
       leap = 1;
   }
  
   if(y%400 == 0)
   {
       leap = 1;
   }
  
   if(leap)
       printf("\nYES\n\n");
   else
       printf("\nNO\n\n");
}

Screenshot: ( for reference )

Output:

Note: If you have any doubts please comment.

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