In: Statistics and Probability
Disadvantage groups, notably Blacks and Hispanics. Have had smaller high school graduation rates and so less access to college than Whites. Among those with college degrees is an educational success beyond college similarly affected? To address this question use the data below. sample of 30-year-old Americans with college degrees.
Highest Degree. Whites Black Hispanic Row Totals
College 5030 549 412 5991
Advanced 1324 117 99 1540
Columm totals 6354 668 511 7634 (grand)
a) state appropriate hypotheses
b) Find the degree of freedom
Compute the expected values for the entries for Hispanics. Compute the corresponding contributions to x2. To save time here are the contributions of x2 from the cells of white and blacks: 0.12, 0.7, 0.47, and 2.70.
d) conduct the appropriate test and give (an estimate of) p-value.
e) give an appropriate conclusion in statistical and everyday language.
Solution:
Here, we have to use chi square test for independence of two categorical variables.
a) state appropriate hypotheses
Null hypothesis: H0: Among those with college degrees is an educational success beyond college not similarly affected.
Alternative hypothesis: Ha: Among those with college degrees is an educational success beyond college similarly affected.
We assume level of significance = α = 0.05
Test statistic formula is given as below:
Chi square = ∑[(O – E)^2/E]
Where, O is observed frequencies and E is expected frequencies.
E = row total * column total / Grand total
b) Find the degree of freedom
We are given
Number of rows = r = 2
Number of columns = c = 3
Degrees of freedom = df = (r – 1)*(c – 1) = 1*2 = 2
α = 0.05
Critical value = 5.991465
(by using Chi square table or excel)
Compute the expected values for the entries for Hispanics.
Calculation tables for test statistic are given as below:
Observed Frequencies |
||||
Column variable |
||||
Row variable |
White |
Black |
Hispanic |
Total |
College |
5030 |
549 |
412 |
5991 |
Advanced |
1324 |
117 |
99 |
1540 |
Total |
6354 |
666 |
511 |
7531 |
Expected Frequencies |
||||
Column variable |
||||
Row variable |
White |
Black |
Hispanic |
Total |
College |
5054.683 |
529.8109 |
406.5066 |
5991 |
Advanced |
1299.317 |
136.1891 |
104.4934 |
1540 |
Total |
6354 |
666 |
511 |
7531 |
Calculations |
||
(O - E) |
||
-24.6825 |
19.18909 |
5.493427 |
24.68251 |
-19.1891 |
-5.49343 |
(O - E)^2/E |
||
0.120527 |
0.695005 |
0.074237 |
0.468882 |
2.703748 |
0.2888 |
expected values for the entries for Hispanics = 0.07, 0.29
d) conduct the appropriate test and give (an estimate of) p-value.
Chi square = ∑[(O – E)^2/E] = 4.351199
P-value = 0.11354
(By using Chi square table or excel)
e) give an appropriate conclusion in statistical and everyday language.
P-value > α = 0.05
So, we do not reject the null hypothesis
There is insufficient evidence to conclude that among those with college degrees is an educational success beyond college similarly affected.