In: Chemistry
A sealed container holding 0.0255 L of an ideal gas at 0.993 atm and 67 °C is placed into a refrigerator and cooled to 45 °C with no change in volume. Calculate the final pressure of the gas.
Intila final
V1 = 0.0255L V2 = 0.0255L
P1 = 0.993atm P2 =
T1 = 670C = 67+ 273 = 340K T2 = 450C = 45+273 = 318K
P1V1/T1 = P2V2/T2
P2 = P1V1T2/T1V2
= 0.993*0.0255*318/340*0.0255
= 0.928atm >>>>>answer