Question
In: Statistics and Probability
2. The proportion of people who wait more than an hour at the Social Security Office is...
2. The proportion of people who wait more than an hour at the Social Security Office is 28%. Use this information to answer the following questions:
A. If you randomly select 45 people what is the probability that at least 34% of them will wait more than an hour?
B. If you randomly select 60 people what is the probability that between 25% and 30% of them will wait more than an hour?
C. If you randomly select 150 people what is the probability that less than 23% of them will wait more than an hour?
Solutions
Expert Solution
Let p denotes the true proportion of people who will wait more than an hour.
A)
B)
C)
orchestra answered 1 year agoRelated Solutions
2. The proportion of people who wait more than an hour at the Social Security Office...
2.
The proportion of people who wait more than an hour at the Social
Security Office is 28%. Use this information to answer the
following questions:
A.
If you randomly select 45 people what is the probability that at
least 34% of them will wait more than an hour?
B.
If you randomly select 60 people what is the probability that
between 25% and 30% of them will wait more than an hour?
C.
If you randomly select 150 people...
The director of the IRS has been flooded with complaints that people must wait more than...
The director of the IRS has been flooded with complaints that
people must wait more than 45 minutes before seeing an IRS
representative. To determine the validity of these complaints, the
IRS randomly selects 400 people entering IRS offices across the
country and records the times that they must wait
before seeing an IRS representative. The average waiting
time for the sample is 55 minutes with a standard deviation of 15
minutes.
Are the complaints substantiated by the data at alpha...
The director of the IRS has been flooded with complaints that people must wait more than...
The director of the IRS has been flooded with complaints that
people must wait more than 45 minutes before seeing an IRS
representative. To determine the validity of these complaints, the
IRS randomly selects 400 people entering IRS offices across the
country and records the times that they must wait
before seeing an IRS representative. The average waiting
time for the sample is 55 minutes with a standard deviation of 15
minutes.
a. What is the population being studied?
b. Are...
The 2011 National Business Ethics Survey defines “active social networkers” as people who spend more than...
The 2011 National Business Ethics Survey defines “active social
networkers” as people who spend more than 30 percent of the workday
participating on social networking sites. According to the results
of the survey, active social networkers air company linen in
public. Sixty percent would comment on their personal sites about
their company if it was in the news, 53% say they share information
about work projects once a week or more, and more than a third say
they often comment,...
Test the claim that the proportion of people who own cats is smaller than 30% at...
Test the claim that the proportion of people who own cats is
smaller than 30% at the 0.005 significance level.
The null and alternative hypothesis would be:
H0:μ≥0.3H0:μ≥0.3
H1:μ<0.3H1:μ<0.3
H0:μ≤0.3H0:μ≤0.3
H1:μ>0.3H1:μ>0.3
H0:p≤0.3H0:p≤0.3
H1:p>0.3H1:p>0.3
H0:p≥0.3H0:p≥0.3
H1:p<0.3H1:p<0.3
H0:μ=0.3H0:μ=0.3
H1:μ≠0.3H1:μ≠0.3
H0:p=0.3H0:p=0.3
H1:p≠0.3H1:p≠0.3
The test is:
right-tailed
left-tailed
two-tailed
Based on a sample of 700 people, 24% owned cats
The test statistic is: (to 2 decimals)
The p-value is: (to 2 decimals)
Based on this we:
Fail to reject the null hypothesis
Reject the null hypothesis
1-Test the claim that the proportion of people who own cats is smaller than 60% at...
1-Test the claim that the proportion of people who own cats is
smaller than 60% at the 0.05 significance level.
The null and alternative hypothesis would be:
A) H0:μ≥0.6H0:μ≥0.6
H1:μ<0.6H1:μ<0.6
B) H0:μ=0.6H0:μ=0.6
H1:μ≠0.6H1:μ≠0.6
C) H0:p=0.6H0:p=0.6
H1:p≠0.6H1:p≠0.6
D) H0:μ≤0.6H0:μ≤0.6
H1:μ>0.6H1:μ>0.6
E) H0:p≤0.6H0:p≤0.6
H1:p>0.6H1:p>0.6
F) H0:p≥0.6H0:p≥0.6
H1:p<0.6H1:p<0.6
The test is:
A) two-tailed
B) right-tailed
C) left-tailed
Based on a sample of 300 people, 57% owned cats
The p-value is: (to 2 decimals)
Based on this we:...
1) Test the claim that the proportion of people who own cats is smaller than 60%...
1) Test the claim that the proportion of people who own cats is
smaller than 60% at the 0.05 significance level.
The null and alternative hypothesis would be:
H0:p=0.6H0:p=0.6
H1:p≠0.6H1:p≠0.6
H0:μ≥0.6H0:μ≥0.6
H1:μ<0.6H1:μ<0.6
H0:μ=0.6H0:μ=0.6
H1:μ≠0.6H1:μ≠0.6
H0:p≤0.6H0:p≤0.6
H1:p>0.6H1:p>0.6
H0:μ≤0.6H0:μ≤0.6
H1:μ>0.6H1:μ>0.6
H0:p≥0.6H0:p≥0.6
H1:p<0.6H1:p<0.6
The test is:
two-tailed
right-tailed
left-tailed
Based on a sample of 100 people, 59% owned cats
The test statistic is: (to 2 decimals)
The p-value is: (to 2 decimals)
Based on this we:
Fail to reject the null hypothesis
Reject the null...
1. Test the claim that the proportion of people who own cats is significantly different than...
1. Test the claim that the proportion of people who own cats is
significantly different than 30% at the 0.2 significance
level.
The null and alternative hypothesis would be:
a) H0:μ≤0.3
Ha:μ>0.3
b) H0:p≥0.3
Ha:p<0.3
c) H0:μ≥0.3
Ha:μ<0.3
d) H0:p≤0.3
Ha:p>0.3
e) H0:μ=0.3
Ha:μ≠0.3
f) H0:p=0.3
Ha:p≠0.3
The test is:
-left-tailed
-two-tailed
-right-tailed
Based on a sample of 400 people, 31% owned cats
The p-value is: ____? (to 2 decimals)
Based on this we:
Reject the null hypothesis
Fail to...
Jenny wanted to know if people who exercise regularly eat more apples than people who don’t...
Jenny wanted to know if people who exercise regularly eat more
apples than people who don’t exercise regularly. She took a simple
random sample of six people who exercise. Their standard deviation
was 2.00. She then took a new simple random sample of eight people
who don’t exercise. Their standard deviation was 1.51. Please
calculate the test statistic for this experiment; then state the
critical value; then come to a conclusion concerning the null
hypothesis; and then state what the...
The mean wait time at Social Security Offices is 25 minutes with a standard deviation of...
The mean wait time at Social Security Offices is 25 minutes with
a standard deviation of 11 minutes. Use this information to answer
the following questions:
A.
If you randomly select 40 people what is the probability that their
average wait time will be more than 27 minutes?
B.
If you randomly select 75 people what is the probability that their
average wait time will be between 23 and 26 minutes?
C.
If you randomly select 100 people what is...
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