Question
In: Statistics and Probability
An article contained the following observations on degree of polymerization for paper specimens for which viscosity...
An article contained the following observations on degree of polymerization for paper specimens for which viscosity times concentration fell in a certain middle range:
420 425 427 427 432 433 434 437 439 446 447 448 453 454 465 469
Suppose the sample is from a normal population.
(a) Calculate a 95% confidence interval for the population mean, and interpret it.
(b) Calculate a 95% upper confidence bound for the population mean, and interpret it.
Solutions
Expert Solution
Solution-
a) 95% Confidence interval for population mean.
( 433.38,448.62 )
That means that the true population mean is contained in the interval ( 433.38 , 448.62 )
b ) 95% Upper confidence bound for population mean is
448.62
Calculations-
orchestra answered 1 year agoRelated Solutions
An article contained the following observations on degree of polymerization for paper specimens for which viscosity...
An article contained the following observations on degree of
polymerization for paper specimens for which viscosity times
concentration fell in a certain middle range. 418 421 421 422 425
427 431 434 437 439 446 447 448 453 454 462 465
The article also gave the following observations on degree of
polymerization for specimens having viscosity times concentration
in a higher range. 429 430 430 431 436 438 440 441 445 446 447
(a) Construct a comparative boxplot for the...
An article contained the following observations on degree of polymerization for paper specimens for which viscosity...
An article contained the following observations on degree of
polymerization for paper specimens for which viscosity times
concentration fell in a certain middle range:
415
421
422
422
425
427
430
435
436
439
446
446
448
453
457
462
464
(a) Construct a boxplot of the data.
Comment on any interesting features. (Select all that apply.)
The data appears to be centered near 428.There are no
outliers.The data appears to be centered near 438.There is one
outlier.There is little...
Consider the following random sample observations on stabilized viscosity of asphalt specimens. 2081 1977 2037 1842 ...
Consider the following random sample observations on stabilized
viscosity of asphalt specimens.
2081
1977
2037
1842
2074
Suppose that for a particular application, it is required that
true average viscosity be 2000. Is there evidence this requirement
is not satisfied? From previous findings we know that the
population standard deviation, σ = 89.3.
State the appropriate hypotheses. (Use α = 0.05.)
H0: μ ≠ 2000
Ha: μ = 2000
H0: μ > 2000
Ha: μ < 2000
H0: μ...
Read the article from Bloomberg News: iPhone6 Demand Exceeds Supply. Put the observations contained in the...
Read the article from Bloomberg News: iPhone6
Demand Exceeds Supply.
Put the observations contained in the article into a demand and
supply framework; specifically, discuss the factors that
might underly the nature of the demand for the iPhone6,
both short-term and longer-term.
Did Apple incorrectly estimate demand for the iPhone6?
Does the apparent unfilled demand for the iPhone6 mean lost
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someone else also posts the same question with the article but
there was...
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity...
Construct a normal probability plot for the following sample of
observations on coating thickness for low-viscosity paint.
0.83
0.87
0.89
1.02
1.09
1.14
1.27
1.29
1.46
1.51
1.60
1.64
1.67
1.70
1.78
1.83
Determine the z percentile associated with each sample
observation. (Round your answers to two decimal places.)
Sample observation
0.83
0.87
0.89
1.02
1.09
1.14
1.27
1.29
z percentile
Sample observation
1.46
1.51
1.60
1.64
1.67
1.70
1.78
1.83
z percentile
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity...
Construct a normal probability plot for the following sample of
observations on coating thickness for low-viscosity paint. 0.83
0.86 0.86 1.02 1.08 1.12 1.29 1.31 1.46 1.51 1.60 1.63 1.67 1.69
1.74 1.84 Determine the z percentile associated with each sample
observation. (Round your answers to two decimal places.)
dont just calculate , please show step by step
Construct a normal probability plot for the following sample of observations on coating thickness for low-viscosity...
Construct a normal probability plot for the following sample of
observations on coating thickness for low-viscosity paint.
0.84
0.89
0.90
1.02
1.08
1.14
1.28
1.31
1.47
1.47
1.60
1.62
1.66
1.73
1.75
1.81
Determine the z percentile associated with each sample
observation. (Round your answers to two decimal places.)
Sample observation
0.84
0.89
0.90
1.02
1.08
1.14
1.28
1.31
z percentile
Sample observation
1.47
1.47
1.60
1.62
1.66
1.73
1.75
1.81
z percentile
Determine which of the following polymers are the result of polymerization, and which are the result...
Determine which of the following polymers are the result of
polymerization, and which are the result of
post-polymerization processing. Explain!
1. low density polyethylene
2. high density polyethylene
3. phenol-formaldehyde
4. heavily cross-linked polyisoprene (glass trans. temp:
50C)
5. lightly cross-linked polyisoprene (glass trans. temp:
-60C)
Consider the following sample of observations on coating thickness for low-viscosity paint. 0.87 0.88 0.88 1.05...
Consider the following sample of observations on coating
thickness for low-viscosity paint. 0.87 0.88 0.88 1.05 1.09 1.14
1.29 1.31 1.46 1.49 1.59 1.62 1.65 1.71 1.76 1.83 Assume that the
distribution of coating thickness is normal (a normal probability
plot strongly supports this assumption).
(c) Calculate a point estimate of the value that separates the
largest 10% of all values in the thickness distribution from the
remaining 90%. [Hint: Express what you are trying to estimate in
terms of...
An article described an experiment in which observations on various characteristics were made using minichambers of...
An article described an experiment in which observations on
various characteristics were made using minichambers of three
different types: (1) cooler (PVC frames covered with shade cloth),
(2) control (PVC frames only), and (3) warmer (PVC frames covered
with plastic). One of the article's authors kindly supplied the
accompanying data on the difference between air and soil
temperatures (°C).
Cooler
Control
Warmer
1.59
1.92
2.57
1.43
2.00
2.60
1.88
2.19
1.93
1.26
1.12
1.58
1.91
1.78
2.30
1.86
1.84
0.84...
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