Question

In: Statistics and Probability

Consider the following random sample observations on stabilized viscosity of asphalt specimens. 2081   1977   2037   1842  ...

Consider the following random sample observations on stabilized viscosity of asphalt specimens.

2081   1977   2037   1842   2074

Suppose that for a particular application, it is required that true average viscosity be 2000. Is there evidence this requirement is not satisfied? From previous findings we know that the population standard deviation, σ = 89.3.
State the appropriate hypotheses. (Use α = 0.05.)

H0: μ ≠ 2000

Ha: μ = 2000

H0: μ > 2000

Ha: μ < 2000

    

H0: μ = 2000

Ha: μ ≠ 2000

H0: μ < 2000

Ha: μ = 2000


Calculate the sample mean and standard error. (Round your answers to three decimal places.)

Mean      x =
Standard Error      σx =


Test the appropriate hypotheses. (Round your z test statistic to two decimal places and your p-value to four decimal places.)

test statistic      z =
p - value      p-value =


What can you conclude?

Do not reject the null hypothesis. There is strong evidence to conclude that the true average viscosity differs from 2000.

Reject the null hypothesis. There is strong evidence to conclude that the true average viscosity differs from 2000.   

Reject the null hypothesis. There is no evidence to conclude that the true average viscosity differs from 2000.

Do not reject the null hypothesis. There is no evidence to conclude that the true average viscosity differs from 2000.

Solutions

Expert Solution

Values ( X )
2081 6209.44
1977 635.04
2037 1211.04
1842 25664.04
2074 5155.24
Total 10011 38874.8


  
Standard deviation

Standard Error

State the appropriate hypotheses.

H0: μ = 2000

Ha: μ ≠ 2000

Test Statistic :-


Z = 0.0551


Test Criteria :-
Reject null hypothesis if


Result :- Fail to reject null hypothesis

P value = 2 * P ( Z > 0.051 ) = 0.9561

What can you conclude?

Do not reject the null hypothesis. There is no evidence to conclude that the true average viscosity differs from 2000.


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