In: Statistics and Probability
Consider the following random sample observations on stabilized viscosity of asphalt specimens.
2081 | 1977 | 2037 | 1842 | 2074 |
Suppose that for a particular application, it is required that
true average viscosity be 2000. Is there evidence this requirement
is not satisfied? From previous findings we know that the
population standard deviation, σ = 89.3.
State the appropriate hypotheses. (Use α = 0.05.)
H0: μ ≠ 2000
Ha: μ = 2000
H0: μ > 2000
Ha: μ < 2000
H0: μ = 2000
Ha: μ ≠ 2000
H0: μ < 2000
Ha: μ = 2000
Calculate the sample mean and standard error. (Round your answers
to three decimal places.)
Mean | x = | ||
Standard Error | σx = |
Test the appropriate hypotheses. (Round your z test statistic to
two decimal places and your p-value to four decimal places.)
test statistic | z = | ||
p - value | p-value = |
What can you conclude?
Do not reject the null hypothesis. There is strong evidence to conclude that the true average viscosity differs from 2000.
Reject the null hypothesis. There is strong evidence to conclude that the true average viscosity differs from 2000.
Reject the null hypothesis. There is no evidence to conclude that the true average viscosity differs from 2000.
Do not reject the null hypothesis. There is no evidence to conclude that the true average viscosity differs from 2000.
Values ( X ) | ||
2081 | 6209.44 | |
1977 | 635.04 | |
2037 | 1211.04 | |
1842 | 25664.04 | |
2074 | 5155.24 | |
Total | 10011 | 38874.8 |
Standard deviation
Standard Error
State the appropriate hypotheses.
H0: μ = 2000
Ha: μ ≠ 2000
Test Statistic :-
Z = 0.0551
Test Criteria :-
Reject null hypothesis if
Result :- Fail to reject null hypothesis
P value = 2 * P ( Z > 0.051 ) = 0.9561
What can you conclude?
Do not reject the null hypothesis. There is no evidence to conclude that the true average viscosity differs from 2000.