In: Chemistry
Solve for the new pressure in each of the following, with n and V constant:
aA gas with a pressure of 1.25
atm at 60 ∘C is cooled to -24 ∘C.
b. A sample of
N2 with a pressure of 760 mmHg at -70 ∘C is heated to 34 ∘C.
A)
Initial conditons Final conditions
Pressure = P1= 1.25 atm Pressure = P2=
Temp = T1=60C=60+272=333K Temp = T2= -24C= -24+273= 249K
At constant Volume
P1/T1=P2/T2
1.25/333 = P2/249
P2= 0.935 atm
Final pressure = P2= 0.935 atm
B)
For N2
Initial condition Final condition
Pressure = P1= 760 mm Pressure = P2=
Temp = T1= - 70C= - 70+273=203K Temp = T2=34C = 34+273=307K
P1/T1=P2/T2
760/203 = P2/307
P2= 1149.36 torr.