Question
In: Statistics and Probability
Develop a 90% confidence interval for the household income of subscribers. DATA Household Income ($) 58600...
Develop a 90% confidence interval for the household income of subscribers. DATA
| Household Income ($) |
| 58600 |
| 54200 |
| 38500 |
| 148600 |
| 82100 |
| 64400 |
| 86200 |
| 177100 |
| 68300 |
| 67900 |
| 57300 |
| 83600 |
| 77500 |
| 68200 |
| 61900 |
| 57600 |
| 82300 |
| 64600 |
| 61100 |
| 31200 |
| 92600 |
| 68300 |
| 35100 |
| 85700 |
| 140300 |
| 108200 |
| 61100 |
| 33900 |
| 54400 |
| 61200 |
| 58000 |
| 90700 |
| 95200 |
| 50500 |
| 33800 |
| 147400 |
| 92600 |
| 66200 |
| 45700 |
| 60500 |
| 110600 |
| 60300 |
| 75700 |
| 70100 |
| 42100 |
| 41700 |
| 96900 |
| 65700 |
| 50200 |
| 61700 |
| 44500 |
| 51900 |
| 119100 |
| 49200 |
| 39000 |
| 35000 |
| 104700 |
| 49300 |
| 74000 |
| 57100 |
| 51400 |
| 62100 |
| 103000 |
| 97900 |
| 123100 |
| 322500 |
| 54800 |
| 66500 |
| 33700 |
| 73600 |
| 71300 |
| 74200 |
| 70000 |
| 40800 |
| 72500 |
| 53300 |
| 45600 |
| 73900 |
| 83600 |
| 124700 |
| 101600 |
| 205900 |
| 69700 |
| 95700 |
| 46100 |
| 118600 |
| 65400 |
| 149300 |
| 125000 |
| 39800 |
| 83500 |
| 38700 |
| 102400 |
| 57700 |
| 16200 |
| 43100 |
| 43700 |
| 39600 |
| 127500 |
| 33500 |
| 48100 |
| 52800 |
| 54800 |
| 46500 |
| 60400 |
Solutions
Expert Solution
From the given data the following were calculated
| n | 105 |
| Sum | 7835500 |
| Average | 74623.810 |
| SS(Sum of squares) | 1.74735E* 1011 |
| Variance = SS/n-1 | 1680141254.579 |
| Std Dev=Sqrt(Variance) | 40989.5262 |
_________________________________________________________________
sample mean (
)
= 74623.81, Standard Deviation (s) = 40989.526, n = 105
The Zcritical at 
= 0.10 = 1.645
Although population standard deviation is not known, n is large and we can assume Z critical values
The Confidence Interval is given by
ME, where
The Lower Limit = 74623.810 - 6580.287 = 68043.533
The Upper Limit = 74623.810 + 6580.287 = 81204.087
The Confidence Interval is (68043.533 , 81204.087)
_____________________________________________________
If required to 2 decimal places. then the 90% CI is (68043.53, 81204.09)
If required to 1 decimal places. then the 90% CI is (68043.5, 81204.1)
If required to the nearest dollar. then the 90% CI is (68044, 81204)
orchestra answered 1 year agoRelated Solutions
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For children in the low income group, find a
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Give all answers correct to 3 decimal places.
a) Critical value (positive value only):
b) Margin of error:
c) Confidence interval: < pp <
d) Does the confidence interval support the claim that more than
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Confidence interval supports claim
Confidence interval does not support claim
For...
For children in the low income group, find a 90% confidence interval for the proportion of...
For children in the low income group, find a
90% confidence interval for the proportion of children that drew
the nickel too large.
Give all answers correct to 3 decimal places.
a) Critical value (positive value only):
b) Margin of error:
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Confidence interval supports claim
Confidence interval does not support claim
Data shown below...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean...
Refer to the accompanying data set and construct a 90%
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LOADING... Click the icon to view the pulse rates for adult females
and adult males. Construct a 90% confidence interval of the mean
pulse rate for adult females. nothing bpmless thanmuless than
nothing bpm (Round to one decimal place as needed.) Construct a
90% confidence interval of the mean...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean...
Refer to the accompanying data set and construct a 90%
confidence interval estimate of the mean pulse rate of adult
females; then do the same for adult males. Compare the results.
Males Females
87 77
74 92
51 56
60 65
54 54
61 83
51 78
77 85
49 89
62 55
74 34
59 68
66 81
76 79
80 79
63 66
64 66
96 80
45 58
85 61
72 82
62 85
73 72
71 ...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean...
Refer to the accompanying data set and construct a 90%
confidence interval estimate of the mean pulse rate of adult
females; then do the same for adult males. Compare the results.
Males Females
82 83
72 94
48 59
57 64
54 56
62 80
53 78
74 86
53 86
63 58
73 35
61 65
65 85
76 76
83 75
65 64
64 68
93 79
41 59
84 63
74 82
64 82
72 68
70 ...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean...
Refer to the accompanying data set and construct a 90%
confidence interval estimate of the mean pulse rate of adult
females; then do the same for adult males. Compare the results.
Pulse Rates (beats per minute)
Males Females
82 83
72 94
48 59
57 64
54 56
62 80
53 78
74 86
53 86
63 58
73 35
61 65
65 85
76 76
83 75
65 64
64 68
93 79
41 59
84 63
74 82...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean...
Refer to the accompanying data set and construct a 90%
confidence interval estimate of the mean pulse rate of adult
females; then do the same for adult males. Compare the results.
Males
Females
85
71
79
82
71
66
94
79
52
75
59
70
58
74
65
77
53
56
54
86
62
66
83
88
52
58
76
89
79
79
86
91
53
70
88
9
61
65
57
96
72
61
38
69
57
98
64...
Refer to the accompanying data set and construct a 90% confidence interval estimate of the mean...
Refer to the accompanying data set and construct a 90%
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Males
Females
83
79
74
96
51
56
61
67
53
55
59
83
53
78
78
84
52
90
63
58
69
37
61
64
67
86
76
76
80
78
65
64
68
66
97
76
45
62
86
66
75
83
61
80
70
72
73...
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(answer) < pie < (answer)
Note: the "< " listed above are suppos to be
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Given the data below what is the 90% confidence interval of the mean, 22, 23,19. 17,...
Given the data below what is the 90% confidence interval of the
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