Questions
The variable Home Ownership can take on one of two values: 1 if the person living...

  1. The variable Home Ownership can take on one of two values: 1 if the person living in the home owns the home and 0 if the person living in the home does not own the home. This is an example of a __________variable.

8) Using the following probability distribution table of the random variable x, what is the probability of x = 3?

X

P(X)

0

5/15

1

4/15

2

1/15

3

9) The binomial distribution is characterized by situations that are analogous to

A) drawing balls from an urn.

B) coin tossing.

C) counting defects on an item.

D) measuring the length of an item.

In: Statistics and Probability

Suppose x has a distribution with μ = 15 and σ = 7. (a) If a...

Suppose x has a distribution with μ = 15 and σ = 7.

(a) If a random sample of size n = 49 is drawn, find μx, σx and P(15 ≤ x ≤ 17). (Round σx to two decimal places and the probability to four decimal places.)

μx =
σx =
P(15 ≤ x ≤ 17) =


(b) If a random sample of size n = 55 is drawn, find μx, σx and P(15 ≤ x ≤ 17). (Round σx to two decimal places and the probability to four decimal places.)

μx =
σx =
P(15 ≤ x ≤ 17) =


(c) Why should you expect the probability of part (b) to be higher than that of part (a)? (Hint: Consider the standard deviations in parts (a) and (b).)
The standard deviation of part (b) is  ---Select--- smaller than larger than the same as part (a) because of the  ---Select--- smaller same larger sample size. Therefore, the distribution about μx is  ---Select--- narrower the same wider .

In: Statistics and Probability

A random sample is selected from a normal population with a mean mu equals 30 space...

A random sample is selected from a normal population with a mean mu equals 30 space a n d space s tan d a r d space d e v i a t i o n space sigma equals 8. After a treatment is administered to the individuals in the sample, the sample mean is found to be M=33. (a) If the sample consists of n=16 scores is the sample mean sufficient to conclude that the treatment has a significant effect? Use a two tailed test with alpha space equals space 0.05. (b) If a sample consists of n= 64 scores, is the sample mean sufficient to conclude that the teatment has a significant effect? Use a two-tailed test with alpha space equals space 0.05. (c) Comparing your answers for parts a and b explain how the size of the sample influences the outcome of the hypothesis test?

In: Statistics and Probability

A group of students estimated the length of one minute without reference to a watch or​...

A group of students estimated the length of one minute without reference to a watch or​ clock, and the times​ (seconds) are listed below. Use a 0.10 significance level to test the claim that these times are from a population with a mean equal to 60 seconds. Does it appear that students are reasonably good at estimating one​ minute?

80

93

46

76

53

31

69

74

74

54

76

76

103

100

76

What are the null and alternative​ hypotheses?

Determine the test statistic. Round to two decimal places.

Determine the P-value. Round to three decimal places.

State the final conclusion that addresses the original claim.

______ H0. There is ______ evidence to conclude that the original claim that the mean of the population of estimated is 60 seconds _______ correct. It ________ that as a group the students are reasonably good at estimating one minute.

In: Statistics and Probability

A manufacturing process produces 6.6% defective items. What is the probability that in a sample of...

A manufacturing process produces 6.6% defective items. What is the probability that in a sample of 40 items: a. 12% or more will be defective? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability

b. less than 2% will be defective? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability

c) more than 12% or less than 2% will be defective? (Round the z-value to 2 decimal places and the final answer to 4 decimal places.) Probability

In: Statistics and Probability

Suppose that the miles-per-gallon (mpg) rating of passenger cars is normally distributed with a mean and...

Suppose that the miles-per-gallon (mpg) rating of passenger cars is normally distributed with a mean and a standard deviation of 31.6 and 4.9 mpg, respectively.

a. What is the probability that a randomly selected passenger car gets more than 35 mpg? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)

b. What is the probability that the average mpg of two randomly selected passenger cars is more than 35 mpg? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)


c. If two passenger cars are randomly selected, what is the probability that all of the passenger cars get more than 35 mpg? (Round “z” value to 2 decimal places, and final answer to 4 decimal places.)

In: Statistics and Probability

Question 2: The following table provides earnings information about two companies, A Ltd and B Ltd:...

Question 2:

The following table provides earnings information about two companies, A Ltd and B Ltd:

A Ltd B Ltd

Current year’s total earnings

$595 mil

$148 mil

Current year’s total shares outstanding

100 mil

50 mil

Prior year’s earnings per share

$6.50

$3.93

You are also given two different abnormal returns in share price for the current year, -0.026 (i.e., - 2.6%) and -0.017 (i.e., -1.7%), which are calculated from market model equations for A Ltd and B Ltd.

Required:

a) Calculate the forecast error in earnings per share for the current year for both A Ltd and B Ltd

using the random walk model. Show your workings.

b) Referring to research evidence of the information theory and based on your answer in part (a) of this question, briefly explain which abnormal return in share price you should choose for A Ltd and which abnormal return in share price you should choose for B Ltd, respectively. Assume earnings is the only source of new information in the market.

In: Statistics and Probability

How much do college administrators (not teachers or service personnel) make each year? Suppose you read...

How much do college administrators (not teachers or service personnel) make each year? Suppose you read the local newspaper and find that the average annual salary of administrators in the local college is x = $58,940. Assume that σ is known to be $18,340 for college administrator salaries.

(a) Suppose that x = $58,940 is based on a random sample of n = 36 administrators. Find a 90% confidence interval for the population mean annual salary of local college administrators. What is the margin of error? (Round your answers to the nearest whole number.)

lower limit     $
upper limit     $
margin of error     $


(b) Suppose that x = $58,940 is based on a random sample of n = 81 administrators. Find a 90% confidence interval for the population mean annual salary of local college administrators. What is the margin of error? (Round your answers to the nearest whole number.)

lower limit     $
upper limit     $
margin of error     $


(c) Suppose that x = $58,940 is based on a random sample of n = 121 administrators. Find a 90% confidence interval for the population mean annual salary of local college administrators. What is the margin of error? (Round your answers to the nearest whole number.)

lower limit     $
upper limit     $
margin of error     $

In: Statistics and Probability

The data below is a random sample of 3 observations drawn from the United States population....

The data below is a random sample of 3 observations drawn from the United States population. Use the data to answer the following questions

i. Find 95% confidence intervals of the population mean of experience and wage.

ii. Estimate ρe,w, the correlation between the variables experience and wage.

iii. Find βˆ 1 and βˆ 0, the estimates of the parameters in the following regression equation wage = β0 + β1education + ϵ

iv. Predict wages for a person with 15 years of education using your regression estimate.

v. Find the R2

wage education

16.20 12

12.36 13

14.40 12

12.00 12

In: Statistics and Probability

Having trouble finding the answer. My answer is it is not significantly different 2. Consider a...

Having trouble finding the answer. My answer is it is not significantly different

2. Consider a population of lizards living on an island. We believe that they may be members of a species called Tribolonotus gracilis. The mean length of Tribolonotus gracilis is known to be 8cm. The following length values (cm) were obtained for a sample of individuals from the island:

11.3,11.5, 9.2, 11, 6.9, 8.9, 6.9, 11.3

Do these lizards have sizes that are consistent with their being Tribolonotus gracilis or not? (Base your decision on the observed vs. expected mean length.)

A. Use the correct syntax for null and alternative hypothesis.

B. record tcalc, tcrit and alpha which is .05/2 since it is a two tailed test.

C. State your Statistical Conclusion

D. State your Biological Conclusion

E. include p-value.

G. use the phrase "significantly smaller", "significantly larger" or "not significantly different"

In: Statistics and Probability

The 2015 American Time Use Survey contains data on how many minutes of sleep per night...

The 2015 American Time Use Survey contains data on how many minutes of sleep per night an average college student gets. According to this survey, the minutes that college students sleep per night are right skewed with a mean of 529.9 minutes and standard deviation 135.6 minutes.


Suppose we take a sample of size n = 50 from this same population, and we calculate x̅ = 540 minutes. How many standard deviations, (σ/ √n), away from μ is this sample mean?

In: Statistics and Probability

Proportion Problem. Each year Delta Dental does a survey of parents concerning the tradition of the...

Proportion Problem. Each year Delta Dental does a survey of parents concerning the tradition of the Tooth Fairy. A random sample of 1,058 parents were asked about how much money they leave for a tooth and questions concerning how their child responded to the concept of the Tooth Fairy. In one question, 508 parents indicated that their child saved the money they got for their tooth.

You are asked to calculate a 99% Confidence Interval for this proportion.

.5 is contained in your confidence interval. This is a true or false question

In: Statistics and Probability

The following SPSS output is to test that the average life of bulbs is 1060 hours....

The following SPSS output is to test that the average life of bulbs is 1060 hours.

One-Sample Test

Test Value = 1060 hours

t

Degree freedom

Sig. (2-tailed)

Mean Difference

95% Confidence Interval of the Difference

Lower

Upper

hours

1.963

10

.078

67.273

-9.07

143.61

(a) How many observations are there for this output?

(b) Set up the hypotheses to test the average for this study.

(c) Select the significance level for this study.

(d) What can you conclude about this hypothesis?

(e) What is the value of t-statistic for this study?

(f) Why do you use the t statistic for this study?

In: Statistics and Probability

An insurance company found that 25% of all insurance policies are terminated before their maturity date....

An insurance company found that 25% of all insurance policies are terminated before their maturity date. Assume that 10 polices are randomly selected from the company’s policy database. Out of the 10 randomly selected policies;

a) What is the expected number of policies to be terminated before maturing? [1]

b) What is the standard deviation for the number of policies terminated before maturity? [1]

c) What is the probability that no policy will be terminated before maturity? [1]

d) What is the probability that all policies will be terminated before maturing? [2]

e) What is the probability that at least two policies will be terminated? [3]

f) What is the probability that more than 5 but less than eight policies will be terminated? [3] g) What is the probability that at most eight policies will be terminated? [3]

In: Statistics and Probability

A survey questioned 1,000 men. The survey revealed that 71% of them have visited Disney World...

A survey questioned 1,000 men. The survey revealed that 71% of them have visited Disney World before. Of those who have visited Disney World before, 61% have children. Of those who never visited Disney World before, 68% don't have children. What is the probability that a man selected at random has children?

a) 0.3200

b) 0.6100

c) 0.5259

d) 0.9300

e) 0.0512

f) None of the above.

In: Statistics and Probability