The sale records of a retail store are given in the Excel worksheet "Retail"
Week | Value |
1 | 10.37 |
2 | 5.90 |
3 | 8.70 |
4 | 6.80 |
5 | 7.00 |
6 | 9.87 |
7 | 10.95 |
8 | 10.77 |
9 | 11.15 |
10 | 8.85 |
11 | 13.22 |
12 | 6.02 |
13 | 6.55 |
14 | 9.12 |
15 | 11.77 |
16 | 10.05 |
17 | 10.72 |
18 | 9.40 |
19 | 9.07 |
20 | 12.82 |
21 | 4.92 |
22 | 10.95 |
23 | 13.92 |
24 | 15.62 |
25 | 6.65 |
26 | 13.77 |
27 | 8.77 |
28 | 9.70 |
29 | 8.40 |
30 | 10.35 |
31 | 8.65 |
32 | 6.30 |
33 | 6.40 |
34 | 9.45 |
35 | 9.77 |
36 | 5.42 |
37 | 10.67 |
38 | 7.32 |
39 | 7.20 |
40 | 7.05 |
41 | 9.97 |
42 | 7.72 |
43 | 10.87 |
44 | 7.47 |
45 | 13.05 |
46 | 9.40 |
47 | 12.07 |
48 | 10.40 |
49 | 6.12 |
50 | 12.87 |
51 | 12.05 |
52 | 12.10 |
53 | |
54 | |
55 |
1. Using the moving average method with p = 3 most recent data, the forecast value at time t = 53 is:
a/ 12.34
b/ 10.50
c/ 11.15
d/ 11.32
2. Using the moving average method with p = 3 most recent data, the M A P E is
a/ 9.52%
b/ 39.23%
c/ 26.92%
d/ 40.45%
3. Using the exponential smoothing with alpha = 4, the smoothed SALE at time t = 10 is
a/ 8.87
b/ 9.81
c/ 12.92
d/ 13.15
4. Using the exponential smoothing with alpha = 4, the forecasted SALE at time t = 53 is
a/ 11.49
b/ 14.50
c/ 11.05
d/ 15.53
5. The value of M A D for using exponential smoothing with alpha = 4 to forecast is
a/ 3.66
b/ 2.29
c/ 4.34
d/ 8.76
In: Statistics and Probability
According to Readers Digest, 42% or primary care doctors think their patients receive unnecessary medical care.
a) Suppose a sample of 300 primary care doctors was taken. Show the sampling distribution of the proportion of doctors who think their patients receive unnecessary medical care.
b) What is the probability that the sample proportion will be within
+/- 0.03 of the population proportion?
c) What is the probability that the sample proportion will be within
+/- 0.05 of the population proportion?
d) What would the effect of taking a larger sample be on the probabilities in parts (b) and (c)? Why?
In: Statistics and Probability
Adirondack Savings Bank (ASB) has $1 million in new funds that must be allocated to home loans, personal loans, and automobile loans. The annual rates of return for the three types of loans are 7% for home loans, 12% for personal loans, and 10% for automobile loans. The bank’s planning committee has decided that at least 40% of the new funds must be allocated to home loans. In addition, the planning committee has specified that the amount allocated to personal loans cannot exceed 60% of the amount allocated to automobile loans.
Fill in the blanks
|
In: Statistics and Probability
Find a reference to a poll or study in recent news (last few weeks ideally, earlier if you must.) Did the author include the margin of error? Is this information important? Why or why not?
i don't understand it. please help!
In: Statistics and Probability
A petroleum company has three plants. From a barrel of crude oil, factory #1 can produce 20 gallons of motor oil, 10 gallons of diesel oil and 5 gallons of gasoline. There is also waste in the form of paraffin, among other things. Similarly, factory #2 can produce 4 gallons, 14 gallons, and 5 gallons, respectively, while factory #3 can produce 4 gallons, 5 gallons, and 12 gallons, respectively of motor oil, diesel oil, and gasoline. Factory #1 has 3 gallons of paraffin to dispose of per barrel of crude, factory #2 5 gallons, and factory #3 2 gallons. The current daily demand from distributors is 5000 gallons of motor oil, 8500 gallons of diesel oil and 10000 of gasoline.
QUESTION #5. Suppose factory #3 is shut down by the EPA temporarily for excessive emissions into the atmosphere. If your demand is as it was originally (5000,8500,10000), what would you now say about the companies ability to meet it? What do you recommend they schedule for production now? (Consider the fact that you don’t want to simply tell a client that you can’t solve their problem! They might be paying your company millions of dollars! Offer them lots of options and ideas if you can’t provide exactly what they want.)
In: Statistics and Probability
The Arizona pick 6 "Lotto" lottery says you're a winner if your letter ticket has 3,4,5, or 6 of the winning numbers (of 42 to choose from). If you buy one lottery ticket, what is the probability that your ticket is a loser? PLEASE explain and show how you did this step by step. IM TRYING to actually learn how to do this problem.
In: Statistics and Probability
Binomial or Not Binomial ? … and if it is binomial, give the values of p and n.
The number of diamonds observed when 2 cards are sampled at random (without replacement) from a standard deck of playing cards.
A. Not Binomial B. B( p = _____, n =_____ )
The number of times 2 spots is observed when a fair die is rolled 2 times.
A. Not Binomial B. B( p = _____, n =_____ )
The total number of spots observed when a fair die is rolled 2 times.
A. Not Binomial B. B( p = _____, n =_____ )
The number of times a fair die is rolled until 2 spots is first observed.
A. Not Binomial B. B( p = _____, n =_____ )
The number of diamonds observed when 2 cards are sampled at random (with replacement) from a standard deck of playing cards.
A. Not Binomial B. B( p = _____, n =_____ )
The random variable with distribution given by:
y |
0 |
1 |
2 |
Pr(Y = y) |
.5625 |
.3750 |
.0625 |
A. Not Binomial B. B( p = _____, n =_____ )
The random variable with distribution given by:
y |
0 |
1 |
2 |
3 |
Pr(Y = y) |
.064 |
.278 |
.442 |
.216 |
A. Not Binomial B. B( p = _____, n =_____ )
The random variable with distribution given by:
y |
0 |
1 |
2 |
3 |
4 |
5 |
6 |
Pr(Y = y) |
.000729 |
.010206 |
.059535 |
.185220 |
.324135 |
.302526 |
.117649 |
A. Not Binomial B. B( p = _____, n =_____ )
In: Statistics and Probability
5 more questions from the first post that I made. Posting questions I don't quite understand or need some help with.
Suppose we want a 93% confidence interval for the average amount spent on books by freshmen in their first year at a major university. The interval is to have a margin of error of $2, and the amount spent has a Normal distribution with a standard deviation σ = $30. The number of observations required is CLOSEST to: | |||||||||
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In a statistical test of hypotheses, we say the data are statistically significant at level α if: | |||||||||
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A test statistic in a one-sample t test is described as t(15). From this, we know that the: | |||||||||
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An SRS of 16 items taken from a Normal population yields the average 27.6 and the standard deviation 1.88. To calculate a 95% confidence interval estimate of the population mean, the critical value used in the margin of error is: | |||||||||
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The one-sample t statistic from a sample of n = 21 observations for the two-sided test of H0: μ = 60, Ha: μ ≠ 60 has the value t = –1.98. Based on this information: | |||||||||
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In: Statistics and Probability
The ideal (daytime) noise-level for hospitals is 45 decibels with a standard deviation of 9 db; which is to say, this may not be true. A simple random sample of 70 hospitals at a moment during the day gives a mean noise level of 47 db. Assume that the standard deviation of noise level for all hospitals is really 9 db. All answers to two places after the decimal.
(a) A 99% confidence interval for the actual mean noise level in hospitals is ________ db, ________ db.
(b) We can be 90% confident that the actual mean noise level in hospitals is ________ db with a margin of error of ________ db.
(c) Unless our sample (of 81 hospitals) is among the most unusual 2% of samples, the actual mean noise level in hospitals is between _______ db and ________ db.
(d) A 99.9% confidence interval for the actual mean noise level in hospitals is ________ db , ________ db .
(e) Assuming our sample of hospitals is among the most typical half of such samples, the actual mean noise level in hospitals is between _______ db and ________ db.
(f) We are 95% confident that the actual mean noise level in hospitals is ________ db, with a margin of error of _______ db .
(g) How many hospitals must we examine to have 95% confidence that we have the margin of error to within 1 db?
(h) How many hospitals must we examine to have 99.9% confidence that we have the margin of error to within 1 db?
In: Statistics and Probability
I am using a course that requires me to use excel.I am able to figure everything out except the test statistic
A marine biologist claims that the mean length of mature female pink seaperch is different in fall and winter. A sample of 15 mature female pink seaperch collected in fall has a mean length of 108 millimeters and a standard deviation of 15 millimeters. A sample of 8 mature female pink seaperch collected in winter has a mean length of 106 millimeters and a standard deviation of 13 millimeters. At alphaequals0.02, can you support the marine biologist's claim? Assume the population variances are equal. Assume the samples are random and independent, and the populations are normally distributed. Complete parts (a) through (e) below.
In: Statistics and Probability
One Way ANOVA (Analysis of Variance)
A manufacturer of steel wants to test the effect of the method of manufacture on the tensile strength of a particular type of steel. Four different methods have been tested and the data shown in Table 1. (Use Minitab)
Table 1
Method Tensile Strength
1 6.5 7.6 7.5 6.0
2 9.8 9.7 8.6 8.9
3 7.7 6.2 6.9 7.0
In: Statistics and Probability
A manufacturer of sports equipment has developed a new synthetic fishing line that the company claims has a mean breaking strength of 8 kg with a standard deviation of 0.5 kg. To test the claim, a random sample of 50 lines is tested and found to have a mean breaking strength of (7.8 kg) and a standard deviation of (0.7 kg). Could you conclude that the manufacturer claim justified at 0.01 level of significance?( state any assumptions made)
Subject: Probability and statistics
In: Statistics and Probability
The scores for the sample are as follows:
53, 57, 61, 49, 52, 56, 58, 62, 51, 56
On the basis of this sample, children with a history of preschool day care significantly different from the general population? Use a two-tailed test with α = .05.
a. State the null hypothesis in words and in a statistical form
b. State the alternative hypothesis in words and a statistical form (1).
c.Compute the appropriate statistic to test the hypotheses. Sketch the distribution with the estimated standard error and locate the critical region(s) with the critical value(s) (6). [When you compute SS, you might want to use the definitional formula as it might be easier to compute SS this way].
d. State your statistical decision
e. Compute Cohen’s d. Interpret what this d really means in this context
f. Compute 95% CI
g. What is your conclusion? Interpret the result. Don’t forget to include statistical information as well (e.g., t-score, df, α, Cohen’s d)
In: Statistics and Probability
1.) The Acme Company manufactures widgets. The distribution of
widget weights is bell-shaped. The widget weights have a mean of 65
ounces and a standard deviation of 6 ounces.
Use the Standard Deviation Rule, also known as the Empirical
Rule.
Suggestion: sketch the distribution in order to answer these
questions.
a) 95% of the widget weights lie between and
b) What percentage of the widget weights lie between 59 and 77
ounces? %
c) What percentage of the widget weights lie below 83? %
2.) Engineers must consider the breadths of male heads when
designing helmets. The company researchers have determined that the
population of potential clientele have head breadths that are
normally distributed with a mean of 5.7-in and a standard deviation
of 0.8-in.
In what range would you expect to find the middle 50% of most head
breadths?
Between and
If you were to draw samples of size 53 from this population, in
what range would you expect to find the middle 50% of most averages
for the breadths of male heads in the sample?
Between and
Enter your answers as numbers. Your answers should be accurate to 2
decimal places.
In: Statistics and Probability
Pager (2003) reported that white men with a felony record were as likely to receive a job interview than were black men without a felony record. Using the data below, replicate her findings. Specifically, among 149 black respondents without a felony record, the probability that a potential employer called them for a job interview was .14. Among 53 white respondents with a felony record, the probability that a potential employer called them for a job interview was .17.
A) What is the 95% confidence interval for the probability that black men without a felony were called back for a job interview?
B)Suppose Pager’s research hypothesis was that a criminal record was more important than race in determining the likelihood of employment. Thus, she expected that black men without felonies (BM) were more likely to be interviewed than white men with felonies (WMF). Test the Null Hypothesis of no difference in the likelihoods. State the Null and Research Hypotheses
C)Using a .01 alpha level, determine the critical value of the test.
D)Calculate the obtained value for your test.
E) Interpret the test results.
In: Statistics and Probability