Question

A survey questioned 1,000 men. The survey revealed that 71% of them have visited Disney World before. Of those who have visited Disney World before, 61% have children. Of those who never visited Disney World before, 68% don't have children. What is the probability that a man selected at random has children?

a) 0.3200

b) 0.6100

c) 0.5259

d) 0.9300

e) 0.0512

f) None of the above.

Answer 1

V : Event of a man having visited Disney world

P(V) = 71/100 =0.71

: Event of a man never Disney world

P() = 1-P(V) =1-0.71=0.29

C : Event of a man have children

: Event of a man don't have children

Of those who have visited Disney World before, 61% have children.

Probability that man have children given that the man having visited Disney world : P(C|V) = 0.61

Of those who never visited Disney World before, 68% don't have children

Probability that man don't have children given that the man never visited Disney world : P(|) = 0.68

P(C|) = 1-P(|) =1- 0.68=0.32

Probability that a man selected at random has children = P(C)

Probability that a man selected at random has children = P(C) = 0.5259

probability that a man selected at random has children?

c) 0.5259