Question

Having trouble finding the answer. My answer is it is not significantly different

2. Consider a population of lizards living on an island. We believe that they may be members of a species called Tribolonotus gracilis. The mean length of Tribolonotus gracilis is known to be 8cm. The following length values (cm) were obtained for a sample of individuals from the island:

11.3,11.5, 9.2, 11, 6.9, 8.9, 6.9, 11.3

Do these lizards have sizes that are consistent with their being Tribolonotus gracilis or not? (Base your decision on the observed vs. expected mean length.)

A. Use the correct syntax for null and alternative hypothesis.

B. record tcalc, tcrit and alpha which is .05/2 since it is a two tailed test.

C. State your Statistical Conclusion

D. State your Biological Conclusion

E. include p-value.

G. use the phrase "significantly smaller", "significantly larger" or "not significantly different"

Answer 1

The table given below ,

	X
	11.3	2.8056
	11.5	3.5156
	9.2	0.1806
	11	1.8906
	6.9	7.4256
	8.9	0.5256
	6.9	7.4256
	11.3	2.8056
Sum	77	26.575

From table .Sample size=n=8

Sample mean=

Sample standard deviation=s=

A) Hypothesis : Vs  

B) The critical value is , ; From excel "=TINV(0.05,7)"

The test statistic is ,

C) Decision : Here , the value of the test statistic does not lies in the rejection region.

Therefore , Do not reject the null hypothesis.

D) Conclusion : Hence , There is sufficient evidence to support the claim that the mean length of Tribolonotus gracilis is known to be 8 cm.

E) p-value = ; From excel "=TDIST(2.359,7,2)"

Decision : Here , p-value =0.0504>

Therefore , Do not reject the null hypothesis.

F) Hence , The mean length of Tribolonotus gracilis is not significantly different from 8 cm.