A spaceship has an approximately normal distribution with mean of 521000 spacejugs and a standard deviation of 42000 spacejugs.
a) What is the probability it takes more than 605000 spacejugs of fuel to launch a spaceship?
b) What is the probability it takes between 450,000 and 500000 spacejugs to launch a spaceship?
c) Find the 14th percentile (the point corresponding to the lowest 14%) of fuel used to launch spaceships
In: Statistics and Probability
Mr. James, president of Daniel-James Financial Services, believes that there is a relationship between the number of client contacts and the dollar amount of sales. To document this assertion, he gathered the following information from a sample of clients for the last month. Let X represent the number of times that the client was contacted and Y represent the value of sales ($1000) for each client sampled.
Number of` Sales
Contacts (X) ($1000)
10 26
8 21
12 29
9 27
10 22
a) Compute the regression equation for client contacts and sales. Interpret the slope and intercept parameters.
b) Compute the correlation coefficient and coefficient of determination. Interpret the coefficients.
c) James would like to require 35 client contacts per month. Based upon the above data, predict what the monthly sales would be for this number of client contacts. What would be your advice to Mr. James about his proposed policy?
In: Statistics and Probability
7. The amount of time it takes Alice to make dinner is continuous and uniformly distributed between 10 minutes and 54 minutes. What is the probability that it takes Alice more than 47 minutes to finish making dinner given that it has already taken her more than 40 minutes in the making of her dinner?
9.
The amount of time it takes Isabella to wait for the bus is continuous and uniformly distributed between 4 minutes and 13 minutes. What is the probability that it takes Isabella more than 8 minutes to wait for the bus? Round your answer to three decimal places.
In: Statistics and Probability
Use the confidence level and sample data to find a confidence interval for estimating the population . Round your answer to the same number of decimal places as the sample mean. Test scores: n= 105 x bar =70.5, sigma =6.8; 99% confidence
In: Statistics and Probability
2. Testing conductivity of Corning cookware Based on the seven sample study of the heat conductivity:
0.9 0.75 1 1.2 1.1 0.95 0.92
Estimate or predict the heat conductivity of the Corning Ware for cooking at 90 % confidence.
It would be a t distribution and the sample size less than 30 and we do not know Population Standard deviation.
In: Statistics and Probability
You are interested in finding a 98% confidence interval for the average number of days of class that college students miss each year. The data below show the number of missed days for 11 randomly selected college students. Round answers to 3 decimal places where possible.
6 8 3 4 0 4 6 8 11 6 12
a. To compute the confidence interval use a _____distribution.
b. With 98% confidence the population mean number of days of class that college students miss is between _____and ______days.
c. If many groups of 11 randomly selected non-residential college students are surveyed, then a different confidence interval would be produced from each group. About _____percent of these confidence intervals will contain the true population mean number of missed class days and about _____percent will not contain the true population mean number of missed class days.
In: Statistics and Probability
The drive-up window at a local bank is searching for ways to improve service. One of the tellers has decided to keep a control chart for the service time in minutes for the first four customers driving up to her window each hour for a three-day period. The results for her data collection appear below:
Customer |
TIME |
||||||||
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
1 |
1.4 |
3.8 |
3.6 |
4.3 |
4.0 |
1.3 |
0.9 |
4.7 |
|
2 |
2.3 |
5.2 |
2.5 |
1.2 |
5.2 |
1.1 |
4.4 |
5.1 |
|
3 |
1.9 |
1.9 |
0.8 |
3.0 |
2.7 |
4.9 |
5.1 |
0.9 |
|
4 |
5.1 |
4.8 |
2.9 |
1.5 |
0.3 |
2.3 |
4.6 |
4.7 |
|
Customer |
TIME |
||||||||
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
1 |
2.8 |
0.5 |
4.5 |
0.6 |
4.8 |
2.7 |
4.2 |
0.9 |
|
2 |
3.0 |
2.7 |
1.9 |
1.2 |
2.8 |
2.0 |
1.1 |
4.4 |
|
3 |
4.1 |
4.7 |
4.2 |
2.7 |
1.1 |
2.6 |
4.4 |
0.6 |
|
4 |
4.8 |
3.6 |
0.4 |
2.5 |
0.4 |
2.6 |
3.1 |
0.4 |
|
Customer |
TIME |
||||||||
9 am |
10 am |
11 am |
12 |
1 pm |
2 pm |
3 pm |
4 pm |
||
1 |
0.3 |
3.5 |
5.2 |
2.9 |
3.3 |
4.0 |
2.8 |
0.6 |
|
2 |
2.4 |
3.4 |
0.3 |
1.9 |
3.7 |
3.3 |
0.7 |
2.1 |
|
3 |
5.0 |
4.6 |
2.4 |
0.8 |
3.8 |
5.0 |
1.6 |
3.3 |
|
4 |
0.9 |
3.3 |
3.9 |
0.3 |
2.1 |
2.8 |
4.6 |
2.7 |
|
Using Minitab:
if it's possible i need the minitab file or link for it
In: Statistics and Probability
Hello! I have a question about the following problem, not sure how to approach it...
This is from Mathematical Statistics and Data Analysis, Chapter 11, Problem 11.41
The Hodges-Lehmann shift estimate is defined to be d =median(Xi −Yj), where X1 , X2 , . . . , Xn are independent observations from a distribution F and Y1,Y2,...,Ym are independent observations from a distribution G and are independent of the Xi.
Show that if F and G are normal distributions, then E(d) = μx − μy.
Why is d robust to outliers?
Use the bootstrap to approximate the sampling distribution and the standard error of d.
From the bootstrap approximation to the sampling distribution, form an approximate 90% confidence interval for d
Thank you
In: Statistics and Probability
Refer to the air-conditioning data set aircondit provided in the boot package. The 12 observations are the times in hours between failures of air-conditioning equipment
3, 5, 7, 18, 43, 85, 91, 98, 100, 130, 230, 487.
Assume that the times between failures follow an exponential model Exp(λ). Obtain the MLE of the hazard rate λ and use bootstrap to estimate the bias and standard error of the estimate.
Use R software
In: Statistics and Probability
In his book Chances: Risk and Odds in Everyday Life, James Burke states that there is a 72% chance a polygraph test (lie detector test) will catch a person who is, in fact, lying. Furthermore, there is approximately a 7% chance that the polygraph will falsely accuse someone of lying. (Round your answers to one decimal place.)
(a) Suppose a person answers 90% of a long battery of questions truthfully. What percentage of the answers will the polygraph wrongly indicate are lies? %
(b) Suppose a person answers 10% of a long battery of questions with lies. What percentage of the answers will the polygraph correctly indicate are lies? %
(c) Repeat parts (a) and (b) if 50% of the questions are answered truthfully and 50% are answered with lies.
(a) % (b) %
(d) Repeat parts (a) and (b) if 15% of the questions are answered truthfully and the rest are answered with lies.
(a) % (b) %
In: Statistics and Probability
Suppose we have a binomial experiment in which success is defined to be a particular quality or attribute that interests us.
(a) Suppose n = 43 and p = 0.33. Can we approximate p̂ by a normal distribution? Why? (Use 2 decimal places.)
np = |
nq = |
---Select--- Yes No , p̂ ---Select--- cannot
can be approximated by a normal random variable
because ---Select--- nq exceeds np does not exceed both
np and nq exceed nq does not exceed np and nq do not exceed np
exceeds .
What are the values of μp̂ and
σp̂? (Use 3 decimal places.)
μp̂ = |
σp̂ = |
(b) Suppose n = 25 and p = 0.15. Can we safely
approximate p̂ by a normal distribution? Why or why
not?
---Select--- Yes No , p̂ ---Select--- can
cannot be approximated by a normal random variable
because ---Select--- both np and nq exceed np exceeds nq
does not exceed np does not exceed nq exceeds np and nq do not
exceed .
(c) Suppose n = 65 and p = 0.24. Can we
approximate p̂ by a normal distribution? Why? (Use 2
decimal places.)
np = |
nq = |
---Select--- Yes No , p̂ ---Select--- can
cannot be approximated by a normal random variable
because ---Select--- np does not exceed both np and nq
exceed np exceeds nq does not exceed nq exceeds np and nq do not
exceed .
What are the values of μp̂ and
σp̂? (Use 3 decimal places.)
μp̂ = |
σp̂ = |
In: Statistics and Probability
The shape of the distribution of the time required to get an oil change at a
2020-minute
oil-change facility is unknown. However, records indicate that the mean time is
21.4 minutes21.4 minutes,
and the standard deviation is
4.3 minutes4.3 minutes.
Complete parts (a) through
(c).
(a) To compute probabilities regarding the sample mean using the normal model, what size sample would be required?
A.
The sample size needs to be less than or equal to 30.
B.
The sample size needs to be greater than or equal to 30.
Your answer is correct.
C.
The normal model cannot be used if the shape of the distribution is unknown.
D.
Any sample size could be used.
(b) What is the probability that a random sample of
=45 oil changes results in a sample mean time less than 20 minutes? The probability is approximately __________
In: Statistics and Probability
"First, think twice before you add that purchase to your credit card. If you charged your $2500 spring break trip to your credit card or if you and your spouse just splurged for a $2500 flat screen television and charged it to your credit card, at 18% interest it would take you 34 years and six months to pay it off if you paid a 2% minimum balance and never charged another penny to your credit card."
Set-up an amortization table using the following information to answer the questions.
Total Number of Months: 414 (Make sure to stop your amortization table at the end of month 414.)
Balance: 2500 Interest rate: 18%
Monthly Payment: 2% of the balance but not less than $10
What is the payment amount during the last month (month 414)?
In: Statistics and Probability
22 17
19 10
30 10.5
31 11
32 15
45 6
48 11
49 5.2
68 3
65 4.2
a) Create a scatterplot of this data and comment on the
relationship between the variables
b) Calculate the correlation coefficient between these two
variables
c) Does a linear relationship exist?
d) Calculate the least squares regression equation
e) Using your equation, predict how long we would expect a 43 year
old new hire to remain with the company
In: Statistics and Probability
In each of the following cases, compute 95 percent, 98 percent, and 99 percent confidence intervals for the population proportion p.
(a) pˆ = .5 and n = 97 (Round your answers to 3 decimal places.)
(b) pˆp^ = .1 and n = 315. (Round your answers to 3 decimal places.)
In: Statistics and Probability