Question

In: Statistics and Probability

Question 2 (Modified from Sleuth 7.27) Black wheatears, Oenanthe leucura, are small birds of Spain and...

Question 2 (Modified from Sleuth 7.27) Black wheatears, Oenanthe leucura, are small birds of Spain and Morocco. Males of the species demonstrate an exaggerated sexual display by carrying heavy stones to nesting cavities. Different males carry somewhat different sized stones, prompting a study of whether larger stones may signal a higher health status. M. Soler et al. (1999) calculated the average stone mass (grams) carried by each of 21 male black wheatears, along with T-cell response measurements reflecting their immune systems’ strengths. The data are in ex0727.

(a) (1 point) Make a scatter plot of Mass (X) versus Tcell (Y ) including the estimated regression line.

(b) (2 points) Fit the linear model using the lm() function to regress Tcell on Mass (i.e., model the mean of Tcell as a function of Mass). Use the summary() function to view more information about the estimated regression model. Provide an interpretation for the p-values of the regression coefficients.

(c) (1 point) Construct 90% confidence intervals for the regression parameters using the confint() function.

(d) (1 point) Estimate the mean T-cell measurement for a new bird that is observed to carry stones averaging 4 grams in weight by using the predict() function. Construct a 95% confidence interval for mean T-cell measurement for that new bird.

(e) (1 point) Construct a 95% prediction interval for T-cell measurement for the new bird in part (d). How does the prediction interval compare to the confidence interval from part (d)?

Solutions

Expert Solution

(a) The scatter plot of Mass (X) versus Tcell (Y ) including the estimated regression line is:

(b) The linear model is:

y = 0.033 x + 0.087

(c)

Regression output confidence interval
variables coefficients std. error    t (df=19) p-value 90% lower 90% upper
Intercept 0.0875 0.0787 1.1121 0.2800 -0.0485 0.2235
Mean stone mass (g) 0.0328 0.0106 3.084 .0061 0.0144 0.0512

(d)

Predicted values for: T-cell response (mm)
95% Confidence Interval
Mean stone mass (g) Predicted lower upper
4 0.218783 0.138391 0.299175

(e)

95% Prediction Interval
lower upper
0.031116 0.406450
Bird Mean stone mass (g) T-cell response (mm)
1 3.33 0.252
2 4.62 0.263
3 5.43 0.251
4 5.73 0.251
5 6.12 0.183
6 6.29 0.213
7 6.45 0.332
8 6.51 0.203
9 6.65 0.252
10 6.75 0.342
11 6.81 0.471
12 7.56 0.431
13 7.83 0.312
14 8.02 0.304
15 8.06 0.37
16 8.18 0.381
17 9.08 0.43
18 9.15 0.43
19 9.35 0.213
20 9.42 0.508
21 9.95 0.411
0.334
r   0.578
Std. Error   0.081
n   21
k   1
Dep. Var. T-cell response (mm)
ANOVA table
Source SS   df   MS F p-value
Regression 0.0624 1   0.0624 9.51 .0061
Residual 0.1247 19   0.0066
Total 0.1872 20  
Regression output confidence interval
variables coefficients std. error    t (df=19) p-value 95% lower 95% upper
Intercept 0.0875
Mean stone mass (g) 0.0328 0.0106 3.084 .0061 0.0105 0.0551
Predicted values for: T-cell response (mm)
95% Confidence Interval 95% Prediction Interval
Mean stone mass (g) Predicted lower upper lower upper Leverage
4 0.218783 0.138391 0.299175 0.031116 0.406450 0.225
0.334
r   0.578
Std. Error   0.081
n   21
k   1
Dep. Var. T-cell response (mm)
ANOVA table
Source SS   df   MS F p-value
Regression 0.0624 1   0.0624 9.51 .0061
Residual 0.1247 19   0.0066
Total 0.1872 20  
Regression output confidence interval
variables coefficients std. error    t (df=19) p-value 90% lower 90% upper
Intercept 0.0875 0.0787 1.1121 0.2800 -0.0485 0.2235
Mean stone mass (g) 0.0328 0.0106 3.084 .0061 0.0144 0.0512

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