Question

In: Statistics and Probability

You want to compare housing prices in your community (measured in thousands of dollars) to the...

You want to compare housing prices in your community (measured in thousands of dollars) to the national values of µ= 496, σ= 36.3. Recently, 4 houses on your street were sold for a mean price of 476. Report the standard error of the mean and Z in your answers to the following questions.
Can you conclude that the mean price of housing in your community is different from the national mean at a statistically significant level?
How would your conclusion from a. change if you had obtained a sample of n= 81 with a mean of 483?
How would your conclusion from b. change if you realized that actually σ= 96.3?

Solutions

Expert Solution

We can conduct a hypothesis test for the population mean. we have

n = 4

We want to test whether the mean price differs with the national avg. price. We have the population SD so we can use normal z-test. It is a 2-tailed test.

Test Stat =

standard error =

= 18.15

Test Stat= (476 - 496) / 18.15

= -1.1019

Critical value at = 0.05

= 1.96 ..................Using normal percentage tables at p = 0.025

Since |Test Stat| < Critical value

We do not the reject the null hypothesis at 5%. It is not statistically significant and the mean is 496 significantly.

n = 81

Test Stat =

standard error =

= 4.033

Test Stat= (483 - 496) / 4.033

= -3.223

Critical value at = 0.05

= 1.96 ..................Using normal percentage tables at p = 0.025

Since |Test Stat| > Critical value

We reject the null hypothesis at 5%. It is statistically significant and the mean is not 496 significantly.

n = 4

Test Stat =

standard error =

= 48.15

Test Stat= (476 - 496) / 48.15

= -0.4154

Critical value at = 0.05

= 1.96 ..................Using normal percentage tables at p = 0.025

Since |Test Stat| < Critical value

We do not the reject the null hypothesis at 5%. It is not statistically significant and the mean is 496 significantly.


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