In: Statistics and Probability
In a study of government financial aid for college students, it becomes necessary to estimate the percentage of full time college students who earn a bachelors degree in four years or less. Find the sample size needed to estimate that percentage. Use a 0.05 margin of error and use a confidence level of 99%.
A. Assume that nothing is known about the percentage to be estimated
N =
B. Assume prior studies have shown that about 35% of full time students earn bachelors degrees in four years or less
C. Does the added knowledge in part b have much of an effect on the sample size?
Solution :
Given that,
= 0.5
1 - = 1 - 0.5 = 0.5
margin of error = E = 0.05
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (2.576 / 0.05)2 * 0.5 * 0.5
=663.57
Sample size = 664
(B)
Solution :
Given that,
= 0.35
1 - = 1 - 0.35 = 0.65
margin of error = E = 0.05
At 99% confidence level the z is,
= 1 - 99%
= 1 - 0.99 = 0.01
/2 = 0.005
Z/2 = 2.576 ( Using z table )
Sample size = n = (Z/2 / E)2 * * (1 - )
= (2.576 / 0.05)2 * 0.35 * 0.65
=603.8
Sample size = 604
(C) smaller sample size of the part b