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Brooks Clinic is considering investing in new heart-monitoring equipment. It has two options. Option A would...

Brooks Clinic is considering investing in new heart-monitoring equipment. It has two options. Option A would have an initial lower cost but would require a significant expenditure for rebuilding after 4 years. Option B would require no rebuilding expenditure, but its maintenance costs would be higher. Since the Option B machine is of initial higher quality, it is expected to have a salvage value at the end of its useful life. The following estimates were made of the cash flows. The company’s cost of capital is 5%.

Option A Option B
Initial cost $176,000 $292,000
Annual cash inflows $71,500 $82,400
Annual cash outflows $30,400 $25,400
Cost to rebuild (end of year 4) $51,100 $0
Salvage value $0 $8,800
Estimated useful life 7 years

7 years

Compute the (1) net present value, (2) profitability index, and (3) internal rate of return for each option. (Hint: To solve for internal rate of return, experiment with alternative discount rates to arrive at a net present value of zero.) (If the net present value is negative, use either a negative sign preceding the number eg -45 or parentheses eg (45). Round answers for present value and IRR to 0 decimal places, e.g. 125 and round profitability index to 2 decimal places, e.g. 12.50. For calculation purposes, use 5 decimal places as displayed in the factor table provided.)

Net Present Value Profitability Index Internal Rate of Return
Option A $ %
Option B $ %

Solutions

Expert Solution

Cost of capital 8% Cost of capital 9%
Option A Option B Option A Option B Option A Option B
1.Initial cost -176000 -292000 -176000 -292000 -176000 -292000
2.PV of annual cash inflows
71500*5.78637= 413725.46 372255.455 359855.93
82400*5.78637= 476796.89 429004.89 414715.08
3.PV of annual cash outflows
-30400*5.78637= -175905.65 -158273.65 -153001.68
-25400*5.78637= -146973.80 -132241.80 -127836.93
4. Cost to rebuild at end of 4 yrs.
-51100/1.05^4= -42040.10 0 -37560.03 0 -36200.53 0
5.PV of salvage 0 0 0
8800/1.05^7= 6254.00 5134.72 4813.90
NPV(sum 1 to 5) 19779.71 44077.09 421.78 9897.81 -5346.28 -307.95
Profitability Index=
1+(NPV/Investment)
1+(19779.71/(176000+42040.1)= 1.09
1+(44077.09/292000)= 1.15
NOTE:Annuity Factor---P/A,i=5%; n=7=(1-1.05^-7)/0.05=
5.78637
P/A factors for COC-- 8% & 9%
(1-1.08^-7)/0.08=5.20637
(1-1.09^-7)/0.09=5.03295
IRR by Trial & Error
Trial Cost of capital(as in above   Table) NPV NPV
8% 421.78 9897.81
9% -5346.28 -307.95
Diff. in NPV for 1% 5768.06 10205.76
For NPV to become 0
Disc. Rate to be added= 1%/5768.06*421.78= 1%/10205.76*9897.81=
0.07% 0.97%
So, IRR=     8%+0.07%= 8.07%
        IRR=    8%+0.97%= 8.97%
ANSWERS Net Present Value Profitability Index IRR
Option A $19,779.71 1.09 8.07%
Option B $44,077.09 1.15 8.97%
IRR as per Equation method
ie. NPV=-PV of cash outflows+PV of cash inflows=0
Option A
-176000+(71500*(1-(1+r)^-7)/r)-(30400*(1-(1+r)^-7)/r)-(51100/(1+r)^4)=0
Solving for r, IRR= 8.07%
Option B
-292000+(82400*(1-(1+r)^-7)/r)-(25400*(1-(1+r)^-7)/r)+(8800/(1+r)^7)=0
Solving for r, IRR= 8.97%
IRR(as per Excel)
Option A 0 1 2 3 4 5 6 7
Initial cost -176000
Cash inflow 71500 71500 71500 71500 71500 71500 71500
Cash outflow -30400 -30400 -30400 -30400 -30400 -30400 -30400
Cost to rebuild -51100
Total annual cash flows -176000 41100 41100 41100 -10000 41100 41100 41100
IRR(as per Excel) 8.07%
Option B
Initial cost -292000
Cash inflow 82400 82400 82400 82400 82400 82400 82400
Cash outflow -25400 -25400 -25400 -25400 -25400 -25400 -25400
Salvage 8800
Total annual cash flows -292000 57000 57000 57000 57000 57000 57000 65800
IRR(as per Excel) 8.97%

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