Question

2A. The label on a 1.00-L bottle of wine states that the alcohol content is 12.5% (v/v). How much alcohol is present in the bottle?

2B. How do you make 2.50 L of 3.25 M NaHC03?

2C. How do you make 2.50 L of 0.200 M NaOH?

2D.Tell the type of solution(solid-in-liquid, etc) represented by each of the following: Gasohol, Wax in gasoline, and Gas mixture used as anesthesia

Answer 1

2A.

The v/v percent of the alcohol is 12.5%.

Volume by volume percentage is calculated as follows:

Our solute is the alcohol.

The solution in wine.

Hence, amount of alcohol present in 1.00 L wine bottle is

Hence, the amount of alcohol in the wine bottle is 120 mL.

2B.

Molar mass of NaHCO3 is 84 g/mol

Concentration of the solution to be made = 3.25 M

Volume of the solution = 2.50 L

Hence, number of moles of NaHCO3 present in 2.50 L of 3.25 M solution is

Mass of 8.125 mol of NaHCO3 is

Hence, the procedure to make the required solution will be.

• Weigh in 682.5 g of NaHCO3 in a container.
• Add the NaHCO3 into a big graduated flask.
• Add distilled water till the volume is 2.5 L.

2C.

Molar mass of NaOH is 40 g/mol

Concentration of the solution to be made = 0.200 M

Volume of the solution = 2.50 L

Hence, number of moles of NaOH present in 2.50 L of 0.200 M solution is

Mass of 0.5 mol of NaOH is

Hence, the procedure to make the required solution will be.

• Weigh in 682.5 g of NaOH in a container.
• Add the NaOH into a big graduated flask.
• Add distilled water till the volume is 2.5 L.

2D.

Gasohol -

It is a mixute of gasoline with alcohols like ethanol.

Hence, it is a liquid-in-liquid solution.

Wax in gasoline-

Wax is solid. It is mixed with gasoline(liquid)

Hence, it is a solid-in-liquid solution.

Gas mixture used in anesthesia

As the name suggests, this is a gas-in-gas solution. The gases are generally Nitrous oxide and oxygen.