In: Statistics and Probability
A company that makes cola drinks states that the mean caffeine content per 12-ounce bottle of cola is 55 milligrams. You want to test this claim. During your tests, you find that a random sample of thirty 12-ounce bottles of cola has a mean caffeine content of 54.2 milligrams. Assume the population is normally distributed and the population standard deviation is 6.8 milligrams. At α=0.02
can you reject the company's claim? Complete parts (a) through (e).
(a) Identify Ho and Ha.
(b) Find the critical value(s) and identify the rejectionregion(s). Use technology.
- Identify the rejection region(s)
(c) Find the standardized test statistic. Use technology.
(d) Decide whether to reject or fail to reject the null hypothesis.
(e) Interpret the decision in the context of the original claim
At the 22% significance level, there ▼ (is not or is) enough evidence to ▼(reject or support) the company's claim that the mean caffeine content per 12-ounce bottle of cola ▼(is equal to or is greater than or is different from or is less than) milligrams.
Solution :
= 55
= 54.2
= 6.8
n = 30
This is the two tailed test .
The null and alternative hypothesis is
H0 : = 55
Ha : 55.
= 0.02
The two tailed test critical value = 2.33
z= 0.644≤ zc=2.33
Test statistic = z
= ( - ) / / n
= (54.2 - 55) / 6.8 / 30
= -0.644
P (Z < -0.644) = 0.5193
P-value = 0.5193
= 0.02
0.5193 > 0.02
Do not reject the null hypothesis .
At the 2% significance level, there is not enough evidence to support the company's claim that the mean caffeine content per 12-ounce bottle of cola is different from 55 milligrams.