In: Math
Consider the function f(x)=2e2sin(x). In this question, we will first use a linear approximation to estimate the value of f(0.1). Then, we will use a Taylor polynomial of degree three to estimate de value of f(0.1).
a) What is a good choice for the base point a of the linear approximation and the Taylor polynomial?
Answer: a=
b) Compute the derivative of f and evaluate it at x=a.
Answer: f′(x)=
f′(a)=
c) The linear approximation L(x) of f(x) based at a is:
Answer: L(x)=
d) Use the linear approximation that you have found in (c) to estimate f(0.1).
Answer: f(0.1)≈
e) Compute the second and third derivatives of f.
f′′(x)=
f′′′(x)=
f) Compute f′′(a) and f′′′(a).
f′′(a)=
f′′′(a)=
g) Find the Taylor polynomial of order three of f at the base point a.
T3(x)=
h) Use the Taylor polynomial that you found in (g) to estimate f(0.1).
Answer: f(0.1)≈
i) Compute the error (in absolute value) of the two approximations of f(0.1) that you have found. Give your answer with an accuracy of five decimal places.
Answer: Error for the linear approximation:
Error for the Taylor polynomial of order three:
To appreciate the improvement in the approximation provided by the Taylor polynomial of degree three over the linear approximation, you should sketch the graph of f, L, and T3 near a.