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Consider the function f(x)=2e2sin(x). In this question, we will first use a linear approximation to estimate...

Consider the function f(x)=2e2sin(x). In this question, we will first use a linear approximation to estimate the value of f(0.1). Then, we will use a Taylor polynomial of degree three to estimate de value of f(0.1).

a) What is a good choice for the base point a of the linear approximation and the Taylor polynomial?

Answer: a=

b) Compute the derivative of f and evaluate it at x=a.

Answer: f′(x)=

               f′(a)=

c) The linear approximation L(x) of f(x) based at a is:

Answer: L(x)=

d) Use the linear approximation that you have found in (c) to estimate f(0.1).

Answer: f(0.1)≈    

e) Compute the second and third derivatives of f.

f′′(x)=

f′′′(x)=

f) Compute f′′(a) and f′′′(a).

f′′(a)=

f′′′(a)=

g) Find the Taylor polynomial of order three of f at the base point a.

T3(x)=

h) Use the Taylor polynomial that you found in (g) to estimate f(0.1).

Answer: f(0.1)≈   

i) Compute the error (in absolute value) of the two approximations of f(0.1) that you have found. Give your answer with an accuracy of five decimal places.

Answer: Error for the linear approximation:    

Error for the Taylor polynomial of order three:   

To appreciate the improvement in the approximation provided by the Taylor polynomial of degree three over the linear approximation, you should sketch the graph of f, L, and T3 near a.

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