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In: Statistics and Probability
Use a significance level of 0.05 to test the claim that the average life of cell...
Use a significance level of 0.05 to test the claim that the average life of cell phones equals 5 years. This is done after a study where the following statistical data are collected: n = 27, (x bar) ̅ = 4.6 years and s = 1.9 years. a) Indicates Ho Ha, b) draw the graph, c) find the critical value, d) find the t-statistic, e) performs the hypothesis test to reject or fail to reject the null hypothesis. f) Find the interval at 95% confidence All work must appear to receive credit
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orchestra answered 2 years agoRelated Solutions
Use a significance level of 0.05 to test the claim that the average life of cell...
Use a significance level of 0.05 to test the claim that the
average life of cell phones equals 5 years. This is done after a
study where the following statistical data are collected: n = 27,
(x bar) ̅ = 4.6 years and s = 1.9 years.
a) Indicates Ho Ha,
b) draw the graph,
c) find the critical value,
d) find the t-statistic,
e) performs the hypothesis test to reject or fail to reject the
null hypothesis.
f) Find...
A 0.05 significance level is used for a hypothesis test of the claim that when parents...
A 0.05 significance level is used for a hypothesis test of the
claim that when parents use a particular method of gender
selection, the proportion of baby girls is less than 0.5. Assume
that sample data consists of 78 girls in 169 births, so the sample
statistic of six thirteenths results in a z score that is 1
standard deviation below 0. Complete parts (a) through (h) below.
Identify the null hypothesis and the alternative hypothesis. What
is the value...
A 0.05 significance level is used for a hypothesis test of the claim that when parents...
A 0.05 significance level is used for a hypothesis test of the
claim that when parents use a particular method of gender
selection, the proportion of baby girls is greater than 0.5. Assume
that sample data consists of 45 girls in 81 births, so the sample
statistic of 5/9 (five ninths) results in a z score that is 1
standard deviation above 0. Complete parts (a) through (h)
below.
a. Identify the null hypothesis and the
alternative hypothesis?
b. What...
You wish to test the following claim (Ha) at a significance level of α = 0.05....
You wish to test the following claim (Ha) at a significance
level of α = 0.05.
Ho: μ = 58.9
Ha: μ < 58.9
You believe the population is normally distributed, but you do
not know the standard deviation. You obtain a sample of size n = 34
with mean M = 54.2 and a standard deviation of SD = 8.3.
1. What is the test statistic for this sample? (Report
answer accurate to THREE decimal places.)
test statistic =...
Conduct a hypothesis test with a 5% level of significance on the claim that the average...
Conduct a hypothesis test with a 5% level of
significance on the claim that the average annual salary for a
registered nurse in the state of Washington in 2017 was $55,000.
Plainly state your null and alternative hypothesis, what type of
test you are using, and why.
Data:
61000, 57700, 120100, 8500, 55200,
53000, 40700, 48800, 33800, 50100,
40900, 56300, 56100, 34600, 2100,
42600, 2400, 48600, 21300, 52600,
87900, 29700, 43300, 33200, 41500,
47600, 79100, 38300, 8500, 112000,
10100, 79100,...
You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. For the...
You wish to test the following claim (HaHa) at a significance
level of α=0.05α=0.05. For the context of this problem,
μd=μ2−μ1μd=μ2-μ1 where the first data set represents a pre-test and
the second data set represents a post-test.
Ho:μd=0Ho:μd=0
Ha:μd<0Ha:μd<0
You believe the population of difference scores is normally
distributed, but you do not know the standard deviation. You obtain
pre-test and post-test samples for n=15n=15 subjects. The average
difference (post - pre) is ¯d=−1.5d¯=-1.5 with a standard deviation
of the...
You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. For the...
You wish to test the following claim (HaHa) at a significance
level of α=0.05α=0.05. For the context of this problem,
μd=μ2−μ1μd=μ2-μ1 where the first data set represents a pre-test and
the second data set represents a post-test.
Ho:μd=0Ho:μd=0
Ha:μd>0Ha:μd>0
You believe the population of difference scores is normally
distributed, but you do not know the standard deviation. You obtain
the following sample of data:
pre-test
post-test
52
69
51.6
34.7
48.3
55.4
31.6
46.8
46.4
42.6
31.6
27.1
49.3
49.3...
Test the given claim using the α=0.05 significance level and assuming that the populations are normally...
Test the given claim using the α=0.05 significance level and
assuming that the populations are normally distributed and that the
population variances are equal.
Claim: The treatment population and the placebo population have the
same means.
Treatment group: n=9, x¯=110, s=5.9.
Placebo group: n=7, x¯=116,s=5.7.
The test statistic is =___________
The positive critical value is =__________
The negative critical value is =________
Is there sufficient evidence to warrant the rejection of the claim
that the treatment and placebo populations have...
You wish to test the following claim (HaHa) at a significance level of α=0.05α=0.05. For the...
You wish to test the following claim (HaHa) at a significance
level of α=0.05α=0.05. For the context of this problem, one data
set represents a pre-test and the other data set represents a
post-test.
Ho:μd=0Ho:μd=0
Ha:μd≠0Ha:μd≠0
You believe the population of difference scores is normally
distributed, but you do not know the standard deviation. You obtain
pre-test and post-test samples for n=137n=137 subjects. The average
difference (post - pre) is ¯d=2.2d¯=2.2 with a standard deviation
of the differences of...
Assume that you plan to use a significance level of \alphaα = 0.05 to test the...
Assume that you plan to use a significance level of \alphaα =
0.05 to test the claim that p1 = p2, Use the given sample sizes and
numbers of successes to find the pooled estimate p-bar. Round your
answer to the nearest thousandth. n1 = 236 n2 = 307 x1 = 77 x2 =
66
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