In: Biology
The genes for A, B, C and E assort independently. If a plant with the genotype AaBBCcEe is crossed with a plant with the genotype aaBbccEe, what is the probability of progeny having the genotype aaBbCcee?
AaBBCcEe * aaBbccEe
let`s divide this cross into four different crosses
1) Aa * aa
| A | a | |
| a | Aa | aa | 
| a | Aa | aa | 
probability of getting aa= number of aa/total number=2/4=1/2
2) BB * Bb
| B | b | |
| B | BB | Bb | 
| B | BB | Bb | 
probability of getting Bb= number of Bb/total number=2/4=1/2
3) Cc * cc
| C | c | |
| c | Cc | cc | 
| c | Cc | cc | 
probability of getting Cc= number of Cc/total number=2/4=1/2
4) Ee * Ee
| E | e | |
| E | EE | Ee | 
| e | Ee | ee | 
probability of getting ee= number of ee /total number=1/4
probability of getting aaBbCcee= probability of getting
aa
probability
of getting Bb
probability
of getting Cc
probability of getting ee=1/2
1/2
1/2
1/4=1/32