In: Biology
Three plant genes, A, B, and C, are linked and occur in the following order. Genetic distances are given as map units (m.u.):
A________10 m.u.______B_____0 m.u.__C
The genes underlie the following phenotypes:
A/_ = blue flowers, a/a = white flowers
B/_ = tall stems, b/b = short stems
C/_ = green leaves, c/c = red leaves
You cross two individuals with the following genotypes:
AbC/AbC x aBc/aBc
You testcross the resulting F1. The proportion of offspring that will have blue flowers is _
Answer:
AbC/AbC x aBc/aBc---Parents
AbC / aBc ----------------F1
AbC / aBc (F1) x abc/abc----Test cross
Expectec double crossover frequency = (Single crossover frequency (SCO) b/w a&b) x (Single crossover frequency (SCO) b/w b&c)
= 10% x 0% = 0
| 
 Class of gametes  | 
 Phenotype  | 
 Frequency of reciprocal pair  | 
 Numbers  | 
 Frequency of each class  | 
 Number of progeny frequency * 100 = %  | 
| 
 Parental  | 
 AbC  | 
 1- all recombinant progeny  | 
 1- 0.1 = 0.9  | 
 0.45  | 
 45% (AbC/abc) = blue, short, green  | 
| 
 aBc  | 
 0.45  | 
 45% (aBc/abc) = white, tall, red  | 
|||
| 
 SCO 1  | 
 ABc  | 
 RF in region 1 = SCO1 - DCO  | 
 SCO1 = 0.1 – 0 = 0.1  | 
 0.05  | 
 5% (ABc/abc) = blue, tall, red  | 
| 
 abC  | 
 0.05  | 
 5% (abC/abc) = white, short, green  | 
|||
| 
 SCO 2  | 
 Abc  | 
 RF in region 2 = SCO2 - DCO  | 
 SCO2 = 0-0 = 0  | 
 0  | 
 0% (Abc/abc)  | 
| 
 aBC  | 
 0  | 
 0%(aBC/abc)  | 
|||
| 
 DCO  | 
 ABC  | 
 (RF in region 1) * (RF in region 2)  | 
 0  | 
 0  | 
 0 (ABC/abc)  | 
| 
 abc  | 
 0  | 
 0(abc/abc)  | 
The proportion of offspring that will have blue flowers is 45% + 5% = 50%