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In: Statistics and Probability

A package delivery service wants to compare the proportion of on-time deliveries for two of its...

A package delivery service wants to compare the proportion of on-time deliveries for two of its major service areas. In City A, 377 out of a random sample of 449 deliveries were on time. A random sample of 282 deliveries in City B showed that 220 were on time.

Compute a 99% confidence interval for the difference ?̂ ?????−?̂ ?????

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Expert Solution

We have given,              
              
x1=377          
n1=449          
              
x2=220          
n2=282          
              
Level of significance =   0.01          
Z critical value (by using Z table)=2.576
Estimate for sample proportion 1
              
Estimate for sample proportion 2
  
Confidence interval formula is              

  
=(-0.0181,0.1371)          
              
              
Lower limit for confidence interval=-0.0181
              
Upper limit for confidence interval is=   0.1371

orchestra answered 1 year ago
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