In: Chemistry
Calculate M for trial 1 and 2 show calculation
Weight of Fas: Trial 1-1.00g Trial 2- 1.00 g
Final reading of buret: 18.00 mL 18.00mL
Initial reading of buret: 50.00 mL 50.00mL
V to equivalence pt.: 26.00mL 26.00mL
Molarity of KMnO4: ? ?
stoichiometric equation
2 KMnO4(aq) + 10(NH4)2Fe(SO4)2(aq) + 8H2SO4(aq) -------> 2MnSO4(aq) + 5Fe2(SO4)3(aq) + 10(NH4)2SO4(aq) + K2SO4(aq) + 8H2O
according stoichiometry 2 mole of KMnO4 react with 5 mole of FAS ( the ratio of KMnO4/FAS is 1:5)
Now,
Trial 1
Mazs of FAS = 1.00g
Molar mass of FAS = 392.13g/mol
No of mole of FAS = 1g/392.13g = 0.00255
So , No of mole of KMnO4 reacted = 0.00255/5=0.00051
Volume of FAS consumed = 26ml
Molarity of FAS = (0.00051/26ml)×1000ml = 0.0196M
Trial 2
Volume of FAS consumed
Molarity of FAS = 0.0196M
Note: As per Initial and final burette reading , volume of KMnO4 consumed is 32ml , if it is true Molarity of KMnO4 is 0.0159M for both trials