Question

A particular fruit's weights are normally distributed, with a mean of 651 grams and a standard deviation of 29 grams.

If you pick one fruit at random, what is the probability that it will weigh between 562 grams and 612 grams

Answer 1

ANSWER:

Given data,

A particular fruit's weights are normally distributed, with a mean of 651 grams and a standard deviation of 29 grams.

Mean = = 651

Stnadard deviation = = 29

If you pick one fruit at random, what is the probability that it will weigh between 562 grams and 612 grams

P(562 < x < 612) = P((562-651)/29 < (x-)/ < (612-651)/29)

P(562 < x < 612) = P(-89/29 < z < -39/29)

P(562 < x < 612) = P(-3.07 < z < -1.34)

P(562 < x < 612) = P(z < -1.34) - P(z < -3.07)

P(562 < x < 612) = 0.09012 - 0.00107

P(562 < x < 612) = 0.08905

P(562 < x < 612) = 0.0891 (Rounded to four decimal places)

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