In: Statistics and Probability
1/ Assume that the readings at freezing on a batch of
thermometers are normally distributed with a mean of 0°C and a
standard deviation of 1.00°C. A single thermometer is randomly
selected and tested. Find P31, the
31-percentile. This is the temperature reading separating the
bottom 31% from the top 69%.
P31 = °C
(Round answer to three decimal places)
2/ Engineers must consider the breadths of male heads when
designing helmets. The company researchers have determined that the
population of potential clientele have head breadths that are
normally distributed with a mean of 6.9-in and a standard deviation
of 1.2-in. Due to financial constraints, the helmets will be
designed to fit all men except those with head breadths that are in
the smallest 1.7% or largest 1.7%.
What is the minimum head breadth that will fit the clientele?
min =
What is the maximum head breadth that will fit the clientele?
min =
Enter your answer as a number accurate to 1 decimal place. Answers
obtained using exact z-scores or z-scores rounded
to 3 decimal places are accepted.
3/ The amounts of nicotine in a certain brand of cigarette are
normally distributed with a mean of 0.958 g and a standard
deviation of 0.322 g. Find the probability of randomly selecting a
cigarette with 0.314 g of nicotine or less.
P(X < 0.314 g) =
Enter your answer as a number accurate to 4 decimal places. NOTE:
Answers obtained using exact z-scores or z-scores
rounded to 3 decimal places are accepted.
4/ In the country of United States of Heightlandia, the height
measurements of ten-year-old children are approximately normally
distributed with a mean of 56.5 inches, and standard deviation of 7
inches.
What is the probability that the height of a randomly chosen child
is between 55.4 and 68.2 inches? Do not round
until you get your your final answer, and then round to 3 decimal
places.
Answer= (Round your answer to 3 decimal places.)
5/ A manufacturer knows that their items have a normally
distributed lifespan, with a mean of 6.9 years, and standard
deviation of 2.1 years.
If you randomly purchase one item, what is the probability it will
last longer than 4 years?
Round answer to three decimal places
1) P(Z < z) = 0.31
Or, z = -0.496
Or, (X - )/ = -0.496
Or, (X - 0)/1 = -0.496
Or, X = -0.496
2) P(X < x) = 0.017
Or, P((X - )/ < (x - )/) = 0.017
Or, P(Z < (x - 6.9)/1.2) = 0.017
Or, (x - 6.9)/1.2 = -2.120
Or, x = -2.12 * 1.2 + 6.9
Or, x = 4.4
Min = 4.4
P(X > x) = 0.017
Or, P((X - )/ > (x - )/) = 0.017
Or, P(Z > (x - 6.9)/1.2) = 0.017
Or, P(Z < (x - 6.9)/1.2) = 0.983
Or, (x - 6.9)/1.2 = 2.120
Or, x = 2.12 * 1.2 + 6.9
Or, x = 9.4
Max = 9.4
3) P(X < 0.314)
= P((X - )/ < (0.314 - )/)
= P(Z < (0.314 - 0.958)/0.322)
= P(Z < -2)
= 0.0228
4) P(55.4 < X < 68.2)
= P((55.4 - )/ < (X - )/ < (68.2 - )/ )
= P((55.4 - 56.5)/7 < Z < (68.2 - 56.5)/7)
= P(-0.157 < Z < 1.671)
= P(Z < 1.671) - P(Z < -0.157)
= 0.9526 - 0.4376
= 0.515
5) P(X > 4)
= P((X - )/ > (4 - )/)
= PZ > (4 - 5.6)/2.1)
= P(Z < -0.762)
= 0.223