In: Statistics and Probability
Assume that the readings at freezing on a batch of thermometers are normally distributed with a mean of 0°C and a standard deviation of 1.00°C. A single thermometer is randomly selected and tested. Find P25, the 25-percentile. This is the temperature reading separating the bottom 25% from the top 75%.
Given that,
mean = = 0
standard deviation = = 1
Using standard normal table,
P(Z < z) = 25%
= P(Z < z) = 0.25
= P(Z <-0.67 ) = 0.25
z = -0.67 Using standard normal z table,
Using z-score formula
x= z * +
x=-0.67 *1+0
x= -0.67